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Question #43692

Difficulty: 8/10 | 🟢 Free

The Question

A radioactive source containing N0N_0 nuclei with a decay constant λ\lambda is placed at the origin. It undergoes β−\beta^- decay, emitting electrons of charge −e-e. Through a constant external magnetic confinement mechanism, all emitted electrons are immediately captured into a single circular orbit of radius RR centered at the origin. The electrons continue to orbit indefinitely with a constant speed vv. A small stationary conducting loop of radius rr (r≪Rr \ll R) is placed at the origin, coplanar with the electron orbit. Assuming the external confinement field does not change with time, which of the following expressions represents the magnitude of the induced non-conservative electric field at the rim of the small loop as a function of time tt?

Options

  • A.

    μ0eN0vλr8πR2e−λt\frac{\mu_0 e N_0 v \lambda r}{8 \pi R^2} e^{-\lambda t}

  • B.

    μ0eN0λ2r4Re−λt\frac{\mu_0 e N_0 \lambda^2 r}{4 R} e^{-\lambda t}

  • C.

    μ0eN0vλr4R2e−λt\frac{\mu_0 e N_0 v \lambda r}{4 R^2} e^{-\lambda t}

  • D.

    μ0eN0vλr24πR3e−λt\frac{\mu_0 e N_0 v \lambda r^2}{4 \pi R^3} e^{-\lambda t}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Radioactive Decay Law Dynamics|Magnetic Moment of Orbiting Electron|Faraday’s Law Vector Form

Why This Question Is Tricky

Common Mistakes

This question tests the critical distinction between the instantaneous rate of particle emission (decay rate) and the accumulated circulating charge that forms a steady macroscopic current.

A common trap for students is to reflexively equate the current I(t)I(t) directly to the decay rate e∣dN/dt∣=eλN0e−λte|dN/dt| = e\lambda N_0 e^{-\lambda t}.

This fundamentally misunderstands the magnetic moment of an orbiting electron, where the current is determined by the total accumulated charge divided by the orbital period.

By forcing the student to derive the time-dependent current from the integrated decay function N0(1−e−λt)N_0(1 - e^{-\lambda t}), the problem elegantly links stochastic radioactive decay with deterministic electromagnetic induction.

Taking the derivative of the incorrect flux yields a dimensionally similar but physically flawed expression, heavily penalizing the rote application of formulas without physical reasoning.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterNuclei - Class 12
ConceptRadioactive Decay Law Dynamics
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree