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Question #43689

Difficulty: 8/10 | 🟢 Free

The Question

A stationary nucleus in free space undergoes an annihilation event, releasing a total energy QQ instantaneously as an isotropic burst of gamma radiation. A perfectly absorbing, rigid, flat circular disk of mass MM and radius RR is positioned such that its center is at a distance dd from the nucleus. The central axis of the disk passes through the nucleus. Assuming the disk is initially at rest and free to move, what is the recoil speed vv of the disk immediately after the radiation is completely absorbed? (Assume v≪cv \ll c, where cc is the speed of light in vacuum, and ignore any gravitational effects).

Options

  • A.

    Q4Mc(R2d2+R2)\frac{Q}{4 M c} \left( \frac{R^2}{d^2 + R^2} \right)

  • B.

    Q2Mc(1−dd2+R2)\frac{Q}{2 M c} \left( 1 - \frac{d}{\sqrt{d^2 + R^2}} \right)

  • C.

    Q2Mc(R2d2+R2)\frac{Q}{2 M c} \left( \frac{R^2}{d^2 + R^2} \right)

  • D.

    Q4Mc(1−dd2+R2)\frac{Q}{4 M c} \left( 1 - \frac{d}{\sqrt{d^2 + R^2}} \right)

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Q-value Calculation|Energy Density Locality|Magnitude Ratio Identity

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to distinguish between scalar energy flux and vector momentum flux in radiation pressure problems.

A common trap is to calculate the total energy intercepted by the disk using the solid angle fraction Ehit=Q(1−cos⁡θ0)/2E_{hit} = Q(1 - \cos\theta_0)/2, and then incorrectly assume the net momentum transferred is simply p=Ehit/cp = E_{hit}/c (Option B).

This flawed approach treats the momentum as a scalar and ignores the fact that photons strike the disk at varying angles.

Students must recognize that momentum is a vector quantity; thus, they must integrate the axial component of the photon momentum (dpcos⁡θdp \cos\theta) over the disk's geometry, leading to the correct sin⁡2θ0\sin^2\theta_0 dependence rather than a (1−cos⁡θ0)(1 - \cos\theta_0) dependence.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterNuclei - Class 12
ConceptQ-value Calculation
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree