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Question #43680

Difficulty: 8/10 | 🟢 Free

The Question

A hypothetical superheavy nucleus of initial mass number A0A_0 undergoes a continuous decay process where it loses nucleons. The decay rate is governed by dAdt=−λA\frac{dA}{dt} = -\lambda A, where the decay parameter λ\lambda is not a constant. Instead, λ\lambda depends on the instantaneous surface area SS and volume VV of the nucleus as λ=cSV\lambda = c \frac{S}{V}, where cc is a positive constant with dimensions of [LT−1][L T^{-1}]. Assuming the strong nuclear force maintains a strictly invariant nuclear density ρn\rho_n (nucleons per unit volume) throughout the decay process, what is the time TT required for the nucleus to completely decay (A→0A \to 0)?

Options

  • A.

    1c(3A04πρn)1/3\frac{1}{c} \left( \frac{3A_0}{4\pi \rho_n} \right)^{1/3}

  • B.

    3c(3A04πρn)1/3\frac{3}{c} \left( \frac{3A_0}{4\pi \rho_n} \right)^{1/3}

  • C.

    13c(3A04πρn)1/3\frac{1}{3c} \left( \frac{3A_0}{4\pi \rho_n} \right)^{1/3}

  • D.

    ∞\infty

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Nuclear Density Invariance|Statistical Nature of Decay|Derived Units via Fundamental Constants

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to reconcile statistical decay laws with the physical constraint of nuclear density invariance.

The primary trap is the assumption that the decay constant λ\lambda is a universal, time-independent constant, which would lead to the standard exponential decay law A(t)=A0e−λtA(t) = A_0 e^{-\lambda t} and an infinite time for complete decay (Option D).

By making λ\lambda dependent on the surface-to-volume ratio, the problem couples the statistical decay rate to the geometric shrinkage of the nucleus.

Students must recognize that invariant density forces the nucleus to shrink in radius (R∝A1/3R \propto A^{1/3}) as it loses mass.

Failing to properly apply the chain rule to the coupled differential equation often results in missing the integration factor of 3, leading to Option C.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterNuclei - Class 12
ConceptNuclear Density Invariance
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree