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Question #43678

Difficulty: 8/10 | 🟢 Free

The Question

In the semi-empirical Liquid Drop Model, atomic nuclei are treated as incompressible spherical droplets. Consider two nuclei, Aluminum (27Al^{27}\text{Al}) and Tellurium (125Te^{125}\text{Te}), completely submerged in a hypothetical, non-viscous 'pion fluid' of uniform density ρπ=1.0×1017 kg/m3\rho_\pi = 1.0 \times 10^{17} \text{ kg/m}^3. Both nuclei are released from rest and subjected to a uniform strong-field acceleration gs=1020 m/s2g_s = 10^{20} \text{ m/s}^2. Assume the nuclear density ρ0\rho_0 is invariant for all nuclei and equals 2.3×1017 kg/m32.3 \times 10^{17} \text{ kg/m}^3. Let aAla_{\text{Al}} and aTea_{\text{Te}} be their respective initial accelerations, and FAlF_{\text{Al}} and FTeF_{\text{Te}} be the magnitudes of the buoyant forces exerted on them by the pion fluid. Which of the following represents the correct ratios aAl:aTea_{\text{Al}} : a_{\text{Te}} and FAl:FTeF_{\text{Al}} : F_{\text{Te}}?

Options

  • A.

    aAl:aTe=1:1a_{\text{Al}} : a_{\text{Te}} = 1 : 1 and FAl:FTe=27:125F_{\text{Al}} : F_{\text{Te}} = 27 : 125

  • B.

    aAl:aTe=125:27a_{\text{Al}} : a_{\text{Te}} = 125 : 27 and FAl:FTe=1:1F_{\text{Al}} : F_{\text{Te}} = 1 : 1

  • C.

    aAl:aTe=1:1a_{\text{Al}} : a_{\text{Te}} = 1 : 1 and FAl:FTe=3:5F_{\text{Al}} : F_{\text{Te}} = 3 : 5

  • D.

    aAl:aTe=27:125a_{\text{Al}} : a_{\text{Te}} = 27 : 125 and FAl:FTe=27:125F_{\text{Al}} : F_{\text{Te}} = 27 : 125

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Nuclear Density Invariance|Archimedes' Buoyancy Dynamics|Approximations (Binomial)

Why This Question Is Tricky

Common Mistakes

This question tests the student's understanding of the Liquid Drop Model combined with Archimedes' principle.

The primary trap is the misapplication of scaling laws: students often confuse the radius scaling (R∝A1/3R \propto A^{1/3}) with volume scaling, incorrectly concluding that buoyant force scales as A1/3A^{1/3} (leading to the 3:53:5 trap).

Furthermore, students may incorrectly assume that a heavier nucleus will accelerate differently under a uniform field in a fluid, failing to recognize that both inertial mass and net force scale linearly with volume (and thus AA).

By realizing that nuclear density ρ0\rho_0 is an intensive property invariant of AA, the acceleration becomes purely a function of the density ratio, neutralizing AA as a variable.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterNuclei - Class 12
ConceptNuclear Density Invariance
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree