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Question #43668
The Question
A gas discharge tube contains a mixture of Hydrogen () and Deuterium () atoms. The atoms are excited and emit light corresponding to the first line of the Balmer series (). This emitted light is passed through a Michelson interferometer. As the movable mirror is displaced, the interference fringes periodically wash out (reach minimum visibility) due to the superposition of the slightly different wavelengths from the two isotopes. Assuming the mass of the proton is , the mass of the electron is (with ), and the mass of the Deuterium nucleus is , what is the minimum non-zero path difference introduced by the interferometer at which the fringes completely wash out? (Let be the Rydberg constant for an infinitely massive nucleus).
Options
- A.
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- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Variable_Constraint
Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.
Concepts Behind This Question
Emission vs Absorption|Reduced Mass Effect|Phase Relationship
Why This Question Is Tricky
Common Mistakes
This question tests the integration of the Bohr model's reduced mass effect with wave optics.
A common trap is treating the Rydberg constant as an immutable scalar, ignoring the isotope-dependent frequency shift.
Furthermore, students often confuse the condition for minimum visibility (fringes washing out, ) with the spatial beat period (fringes repeating, ), which incorrectly leads to a path difference twice as large.
By requiring the calculation of the phase shift directly from the wavenumber difference , the problem elegantly bypasses cumbersome wavelength approximations while strictly penalizing conceptual gaps in both modern physics and interferometry.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Atoms - Class 12 |
| Concept | Emission vs Absorption |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |