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Question #43642
The Question
A projectile nucleus of mass and charge is fired with an initial kinetic energy towards a free target nucleus of mass and charge , which is initially at rest in the laboratory frame. During the head-on collision, the target nucleus is excited to a higher internal energy state, absorbing an excitation energy . Assuming the distance of closest approach is strictly greater than the sum of their nuclear radii, what is the value of ? (Here is the permittivity of free space)
Options
- A.
- B.
- C.
- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Variable_Constraint
Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.
Concepts Behind This Question
Distance of Closest Approach|Nuclear Density Invariance|Equilibrium Stability
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to apply energy conservation in an inelastic scattering event.
The primary trap is the 'Reduced Mass Effect' combined with internal excitation.
Students often incorrectly assume that the entire initial kinetic energy is converted into electrostatic potential energy (ignoring the recoil kinetic energy of the target) or they forget to subtract the energy lost to the internal excitation of the target nucleus.
By requiring the calculation of the available energy in the center-of-mass frame (or accounting for lab-frame recoil) and then equating it to the sum of the Coulomb barrier and the inelastic excitation energy, the problem forces a rigorous application of the Work-Energy theorem in a two-body dynamic system.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Atoms - Class 12 |
| Concept | Distance of Closest Approach |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |