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Question #43629
The Question
A beam of electrons is accelerated from rest and directed normally onto the surface of a simple cubic crystal. The surface atoms form a 2D square lattice with a lattice constant . The lowest-order non-zero diffraction maximum in the azimuthal direction (measured from a principal lattice axis) is observed at a polar angle (measured from the surface normal).
The kinetic energy of these incident electrons exactly matches the energy of a photon emitted during the transition of a hydrogen-like ion embedded in a dense plasma. Due to plasma screening, the effective Rydberg energy of this ion is modified to . Assuming the electron diffraction follows the 2D surface Laue condition and taking , what is the value of ?
Options
- A.
- B.
- C.
- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Davisson-Germer Significance|Rydberg Constant Sensitivity|Vector Cross-Products
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to correctly apply the 2D Laue condition for surface diffraction, avoiding the common trap of treating it as a 1D scalar grating problem.
Students often erroneously apply the 1D Bragg-like equation without accounting for the azimuthal angle and the vector nature of the momentum transfer in the reciprocal lattice plane.
By specifying , the effective interplanar spacing is , not .
Furthermore, it links this geometric wave mechanics concept to a modified Bohr model, forcing students to treat the Rydberg constant as an environment-dependent variable rather than a fixed universal constant, thereby testing their fundamental understanding of atomic transitions under screening effects.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Dual Nature of Radiation and Matter - Class 12 |
| Concept | Davisson-Germer Significance |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |