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Question #43586

Difficulty: 8/10 | 🟢 Free

The Question

A monochromatic light beam of wavelength λ\lambda illuminates a single slit of width aa. The resulting diffraction pattern is observed on a screen placed at a distance DD (D≫aD \gg a). A small rectangular photoelectric detector of width ww (w≪λDaw \ll \frac{\lambda D}{a}) and length LL is placed on the screen parallel to the slit. The work function of the detector material is ϕ\phi (where ϕ<hcλ\phi < \frac{hc}{\lambda}). When the detector is centered exactly at the central maximum of the diffraction pattern, it records a saturation photoelectric current i0i_0 and a stopping potential V0V_0. When the detector is moved and centered exactly at the first diffraction minimum, it records a saturation photoelectric current i1i_1 and a stopping potential V1V_1. Assuming the quantum efficiency of the detector is constant and independent of intensity, which of the following expressions correctly gives V1V_1 and the ratio i1i0\frac{i_1}{i_0}?

Options

  • A.

    V1=V0,i1i0=112(awλD)2V_1 = V_0, \quad \frac{i_1}{i_0} = \frac{1}{12} \left( \frac{a w}{\lambda D} \right)^2

  • B.

    V1=0,i1i0=0V_1 = 0, \quad \frac{i_1}{i_0} = 0

  • C.

    V1=V0,i1i0=14(awλD)2V_1 = V_0, \quad \frac{i_1}{i_0} = \frac{1}{4} \left( \frac{a w}{\lambda D} \right)^2

  • D.

    V1=V0,i1i0=112π2(awλD)2V_1 = V_0, \quad \frac{i_1}{i_0} = \frac{1}{12\pi^2} \left( \frac{a w}{\lambda D} \right)^2

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Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Diffraction vs Interference|Intensity and Photon Flux|Stopping Potential Independence|Statistical Calculus

Why This Question Is Tricky

Common Mistakes

Students often fall into the trap of assuming that because the theoretical intensity at a diffraction minimum is zero, the photon flux and consequently the photoelectric current must be exactly zero.

This ignores the physical reality of a finite-width detector integrating over a localized region where the probability density of photons is non-zero.

Furthermore, students may incorrectly assume that a drastically reduced intensity alters the stopping potential, failing to distinguish between the energy of individual photons (which dictates stopping potential via Einstein's photoelectric equation) and the total photon flux (which dictates saturation current).

This question rigorously tests the synthesis of wave optics (Taylor expansion of the diffraction envelope) and quantum physics (independence of stopping potential).

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterWave Optics - Class 12
ConceptDiffraction vs Interference
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree