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Question #43571
The Question
A stationary source at continuously emits a composite wave consisting of two harmonic components with angular frequencies and , where . The waves propagate in the direction through a non-linear dispersive medium. The dispersion relation of the medium is given by , where and are positive constants. At any given instant , what is the spatial distance between two adjacent nodes of the beat envelope?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Variable_Constraint
Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.
Concepts Behind This Question
Superposition Principle|Beats and Frequency Difference|Approximation (Binomial)
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to distinguish between phase velocity and group velocity in a dispersive medium when analyzing beat patterns.
A common misconception is to assume that the spatial beat length can be calculated using , where is the phase velocity (leading to Option B).
However, the beat envelope's spatial structure is governed by the group velocity .
By forcing the derivation of the spatial distance between envelope nodes directly from the superposition principle and the non-linear dispersion relation, the trap of using the standard non-dispersive kinematic formula is exposed.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Wave Optics - Class 12 |
| Concept | Superposition Principle |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |