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Question #43557

Difficulty: 8/10 | 🟢 Free

The Question

An astronomical telescope is modified by replacing its standard objective lens with a solid glass sphere of radius R=10 cmR = 10 \text{ cm} and refractive index μ=1.5\mu = 1.5. To collect more light, a thin converging lens L1L_1 of focal length f1=30 cmf_1 = 30 \text{ cm} is placed coaxially in front of the sphere such that the center of the sphere is at a distance d=20 cmd = 20 \text{ cm} from L1L_1. Parallel light rays from a distant star enter L1L_1, pass through the glass sphere, and are finally viewed through an eyepiece (a thin converging lens of focal length fe=5 cmf_e = 5 \text{ cm}). If the entire system is in normal adjustment (final image at infinity), what is the distance between the center of the glass sphere and the eyepiece?

Options

  • A.

    11 cm11 \text{ cm}

  • B.

    15 cm15 \text{ cm}

  • C.

    20 cm20 \text{ cm}

  • D.

    26 cm26 \text{ cm}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Telescope Normal Adjustment|Virtual Object Trap|Lens Maker’s Formula Constraints

Why This Question Is Tricky

Common Mistakes

Students incorrectly apply the standard telescope tube length formula L=fo+feL = f_o + f_e or assume the objective lens receives parallel rays.

By introducing a preceding lens, the thick spherical objective receives converging rays, creating a 'Virtual Object Trap'.

Students must abandon thin-lens approximations and sequentially apply the spherical refraction formula to both surfaces of the thick lens to find the true position of the intermediate image, before applying the normal adjustment condition for the eyepiece.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterRay Optics and Optical Instruments - Class 12
ConceptTelescope Normal Adjustment
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree