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Question #43546

Difficulty: 8/10 | 🟢 Free

The Question

A particle of mass mm is constrained to move along the positive x-axis. Its potential energy is given by U(x)=U0[13(ax)3−12(ax)2]U(x) = U_0 \left[ \frac{1}{3} \left(\frac{a}{x}\right)^3 - \frac{1}{2} \left(\frac{a}{x}\right)^2 \right] where U0U_0 and aa are positive constants. The particle is initially at rest at its stable equilibrium position. A short impulse JJ is delivered to the particle in the positive x-direction. Given that J≪mU0J \ll \sqrt{m U_0}, the maximum x-coordinate reached by the particle is approximately:

Options

  • A.

    a+JamU0a + \frac{J a}{\sqrt{m U_0}}

  • B.

    a+Ja2mU0a + \frac{J a}{\sqrt{2 m U_0}}

  • C.

    a+2JamU0a + \frac{2 J a}{\sqrt{m U_0}}

  • D.

    JamU0\frac{J a}{\sqrt{m U_0}}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

SHM Definition via Differential Equation|Interatomic Force Curve|Stress vs. Strain Definition

Why This Question Is Tricky

Common Mistakes

This question tests the ability to model small oscillations in an arbitrary non-linear potential well, a core JEE Advanced concept.

The primary trap lies in the miscalculation of the effective spring constant keffk_{eff}.

Students often confuse the Taylor expansion term 12U′′(x0)(Δx)2\frac{1}{2}U''(x_0)(\Delta x)^2 with U′′(x0)(Δx)2U''(x_0)(\Delta x)^2, leading to a missing factor of 1/21/2 in the energy equation and incorrectly selecting Option B.

Additionally, Option D traps students who calculate the amplitude correctly but forget to add the equilibrium offset x0x_0.

The problem forces the use of the Work-Energy theorem in a localized quadratic approximation, as the exact potential cannot be solved algebraically for xmaxx_{max} without it.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterOscillations - Class 11 Part 2
ConceptSHM Definition via Differential Equation
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree