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Question #43541

Difficulty: 8/10 | 🟢 Free

The Question

In a 1D model of a crystalline solid, an atom of mass MM is bound in an anharmonic potential given by U(x)=12kx2−gx3U(x) = \frac{1}{2} k x^2 - g x^3, where xx is the displacement from its equilibrium position at 0 K0\text{ K}, and kk and gg are positive constants. At a thermodynamic temperature TT, the time-averaged mean displacement of the atom due to thermal agitation is observed to be ⟨x⟩=αT\langle x \rangle = \alpha T, where α\alpha is a positive constant. The atom undergoes small oscillations about this new mean position. Assuming kBk_B is the Boltzmann constant and the thermal energy is small enough that 12k⟨x2⟩≈12kBT\frac{1}{2}k\langle x^2 \rangle \approx \frac{1}{2}k_B T, which of the following expressions represents the time period of these small oscillations at temperature TT?

Options

  • A.

    2πMk(1−2α2kTkB)2\pi \sqrt{\frac{M}{k \left( 1 - \frac{2 \alpha^2 k T}{k_B} \right)}}

  • B.

    2πMk(1−3α2kTkB)2\pi \sqrt{\frac{M}{k \left( 1 - \frac{3 \alpha^2 k T}{k_B} \right)}}

  • C.

    2πMk(1+2α2kTkB)2\pi \sqrt{\frac{M}{k \left( 1 + \frac{2 \alpha^2 k T}{k_B} \right)}}

  • D.

    2πMk2\pi \sqrt{\frac{M}{k}}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Thermal Expansion of Area and Volume|Effective Spring Constant|Interatomic Force Curve

Why This Question Is Tricky

Common Mistakes

This question tests the fundamental microscopic origin of thermal expansion and its effect on elasticity.

Students often incorrectly assume that the spring constant 'k' remains invariant under thermal expansion (the Hooke's Law paradigm).

However, thermal expansion only occurs because the interatomic potential is anharmonic (non-linear).

As temperature increases, the mean separation increases, moving the atom to a region where the potential well is shallower.

By applying the condition that the time-averaged force is zero and using the equipartition theorem, students must find the anharmonic coefficient 'g' and evaluate the second derivative of the potential at the new mean position to find the temperature-dependent effective spring constant.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterThermal Properties of Matter - Class 11 Part 2
ConceptThermal Expansion of Area and Volume
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree