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Question #43523
The Question
A newly formed solid spherical planet of total mass (in ) and radius (in ) is in hydrostatic equilibrium under its own gravity. The planet can be assumed to have a uniform density. The material of the planet has a bulk modulus (in ) and a coefficient of linear thermal expansion (in ). Due to intense internal radioactive decay, the temperature of a small central core region of the planet increases by (in ), while the massive outer layers remain at their initial temperature. Assuming the outer layers act as a perfectly rigid constraint that prevents any volume expansion of the core, the total compressive stress at the center of the planet reaches the material's breaking stress (in ). Which of the following expressions correctly represents ? (Here is the universal gravitational constant in ).
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Multi-Concept_Bridge
Master problems that require linking physics and math concepts to solve complex competitive questions.
Concepts Behind This Question
Gravitational Self-Energy|Breaking Stress Concept|Integration
Why This Question Is Tricky
Common Mistakes
This question tests two distinct physical traps common in JEE Advanced.
First, students often misapply the simplified hydrostatic pressure formula (using surface gravity and depth ), which incorrectly yields a central pressure of .
The correct approach requires integrating the varying gravitational field from the surface to the core.
Second, students frequently confuse linear and volumetric thermal stress in 3D constrained systems, mistakenly using the linear expansion coefficient instead of the volumetric coefficient when calculating the constrained thermal pressure .
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Gravitation - Class 11 Part 1 |
| Concept | Gravitational Self-Energy |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |