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Question #43512
The Question
A satellite of instantaneous mass is in a nearly circular orbit around a planet of mass (). The satellite passes through a uniform, stationary dust cloud, accreting dust at a constant rate . Due to this accretion, the satellite's instantaneous equilibrium circular orbit radius slowly shrinks. The satellite undergoes small radial oscillations such that its radial distance is , where . Assume the fractional change in mass during one oscillation is negligible. The differential equation governing these small radial oscillations can be mapped to the equation of a damped L-C-R circuit: . If the radial displacement is analogous to the charge , and the instantaneous mass is analogous to the inductance , what are the equivalent resistance and capacitance of the circuit?
Options
- A.
,
- B.
,
- C.
,
- D.
,
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Multi-Concept_Bridge
Master problems that require linking physics and math concepts to solve complex competitive questions.
Concepts Behind This Question
Orbital Velocity Energy Balance|L-C Circuit Analogy|Differential Equation
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to correctly apply Newton's Second Law for variable mass systems and linearize the resulting effective potential.
The core trap lies in ignoring the momentum transfer from the accreted stationary dust, which acts as a non-conservative drag force.
Students who incorrectly apply the static Virial Theorem or standard constant-mass orbital mechanics will miss the damping term, leading to .
Furthermore, recognizing that the angular momentum of the satellite-dust system is conserved (since external torque is zero) is crucial to correctly formulating the centrifugal term and finding the correct effective capacitance .
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Gravitation - Class 11 Part 1 |
| Concept | Orbital Velocity Energy Balance |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |