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Question #43512

Difficulty: 8/10 | 🟢 Free

The Question

A satellite of instantaneous mass mm is in a nearly circular orbit around a planet of mass MM (M≫mM \gg m). The satellite passes through a uniform, stationary dust cloud, accreting dust at a constant rate dmdt=λ\frac{dm}{dt} = \lambda. Due to this accretion, the satellite's instantaneous equilibrium circular orbit radius rcr_c slowly shrinks. The satellite undergoes small radial oscillations xx such that its radial distance is r(t)=rc+x(t)r(t) = r_c + x(t), where x≪rcx \ll r_c. Assume the fractional change in mass during one oscillation is negligible. The differential equation governing these small radial oscillations can be mapped to the equation of a damped L-C-R circuit: Led2qdt2+Redqdt+qCe=0L_e \frac{d^2q}{dt^2} + R_e \frac{dq}{dt} + \frac{q}{C_e} = 0. If the radial displacement xx is analogous to the charge qq, and the instantaneous mass mm is analogous to the inductance LeL_e, what are the equivalent resistance ReR_e and capacitance CeC_e of the circuit?

Options

  • A.

    Re=λR_e = \lambda, Ce=rc3GMmC_e = \frac{r_c^3}{GMm}

  • B.

    Re=0R_e = 0, Ce=rc3GMmC_e = \frac{r_c^3}{GMm}

  • C.

    Re=λR_e = \lambda, Ce=rc33GMmC_e = \frac{r_c^3}{3GMm}

  • D.

    Re=λ2R_e = \frac{\lambda}{2}, Ce=rc32GMmC_e = \frac{r_c^3}{2GMm}

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Correct Answer

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Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Orbital Velocity Energy Balance|L-C Circuit Analogy|Differential Equation

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to correctly apply Newton's Second Law for variable mass systems and linearize the resulting effective potential.

The core trap lies in ignoring the momentum transfer from the accreted stationary dust, which acts as a non-conservative drag force.

Students who incorrectly apply the static Virial Theorem or standard constant-mass orbital mechanics will miss the λr˙\lambda \dot{r} damping term, leading to Re=0R_e = 0.

Furthermore, recognizing that the angular momentum of the satellite-dust system is conserved (since external torque is zero) is crucial to correctly formulating the centrifugal term J2mr3\frac{J^2}{mr^3} and finding the correct effective capacitance CeC_e.

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Question Information

SubjectPhysics
ChapterGravitation - Class 11 Part 1
ConceptOrbital Velocity Energy Balance
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree