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Question #43503

Difficulty: 8/10 | 🟢 Free

The Question

A conducting rod of mass mm and length ll is placed on two long, frictionless, horizontal conducting rails. A uniform vertical magnetic field BB exists throughout the region. The rails are connected at one end by a non-ohmic electronic device. The dynamic resistance of this device is defined as Rd=dVdI=αIR_d = \frac{dV}{dI} = \alpha I, where VV is the voltage drop across the device, II is the current through it (I≥0I \ge 0), and α\alpha is a positive constant. Assume V=0V=0 when I=0I=0. The rod is given an initial velocity v0v_0 parallel to the rails. Neglecting the electrical resistance of the rod and the rails, and ignoring any self-inductance in the circuit, what is the total distance xfx_f the rod travels before coming to rest?

Options

  • A.

    2mαv03/23(Bl)3/2\frac{\sqrt{2} m \sqrt{\alpha} v_0^{3/2}}{3 (B l)^{3/2}}

  • B.

    2mαv03/23(Bl)3/2\frac{2 m \sqrt{\alpha} v_0^{3/2}}{3 (B l)^{3/2}}

  • C.

    mαv03/23(Bl)3/2\frac{m \sqrt{\alpha} v_0^{3/2}}{3 (B l)^{3/2}}

  • D.

    22mαv03/23(Bl)3/2\frac{2\sqrt{2} m \sqrt{\alpha} v_0^{3/2}}{3 (B l)^{3/2}}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Power-Velocity Relationship|Dynamic Resistance (AC Resistance)|Cell EMF vs Terminal Voltage

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to correctly apply the concept of dynamic resistance in a coupled electromechanical system.

The lethal trap lies in the misapplication of Ohm's Law for power or voltage in non-ohmic devices.

Students commonly assume that voltage is simply V=IRd=αI2V = I R_d = \alpha I^2, or that power dissipated is P=I2Rd=αI3P = I^2 R_d = \alpha I^3.

Both assumptions fail because dynamic resistance is a differential quantity (Rd=dV/dIR_d = dV/dI).

The correct macroscopic voltage must be found via integration (V=∫RddI=12αI2V = \int R_d dI = \frac{1}{2}\alpha I^2).

Failing to integrate introduces a missing factor of 1/21/2 in the voltage-current relationship, leading directly to the incorrect coefficient in Option B.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterWork, Energy, and Power - Class 11 Part 1
ConceptPower-Velocity Relationship
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree