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Question #43483

Difficulty: 8/10 | 🟢 Free

The Question

The velocity-time (v−tv-t) graph of a particle moving along the x-axis exhibits changing concavity and is modeled by the equation v(t)=4t3−12t2+16v(t) = 4t^3 - 12t^2 + 16, where vv is in m/s\text{m/s} and tt is in seconds. Determine the average speed of the particle over the time interval from t=0t = 0 to t=3 st = 3 \text{ s}.

Options

  • A.

    7 m/s7 \text{ m/s}

  • B.

    10 m/s10 \text{ m/s}

  • C.

    16 m/s16 \text{ m/s}

  • D.

    21 m/s21 \text{ m/s}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Non-Uniform Acceleration Constraint|Graphical Concavity Significance|Average Speed Ambiguity

Why This Question Is Tricky

Common Mistakes

This question tests the fundamental definition of average speed for non-uniformly accelerated motion.

Students often fall into the trap of using the kinematic shortcut vavg=(u+v)/2v_{avg} = (u+v)/2, which yields 16 m/s16 \text{ m/s} here.

This formula is strictly valid only for constant acceleration (linear v−tv-t graphs).

By providing a cubic v−tv-t function with an inflection point, the acceleration is explicitly non-uniform and changes sign.

The correct approach requires recognizing that average speed is the time-averaged integral of the velocity function, forcing the use of calculus.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMotion in a Straight Line - Class 11 Part 1
ConceptNon-Uniform Acceleration Constraint
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree