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Question #43468
The Question
A photo-diode is modeled as an ideal AC current source in parallel with its voltage-dependent junction capacitance . The internal shunt resistance of the diode is assumed to be infinite. The junction capacitance varies with the applied DC reverse bias voltage (in Volts) according to the relation , where (in Farads) is the zero-bias capacitance and (in Volts) is the built-in potential. The photo-diode is connected to an external series combination of an inductor (in Henrys) and a resistor (in Ohms). An ideal biasing network maintains the DC reverse bias across the diode without affecting the AC impedance of the circuit. The intensity of the incident light is modulated at an angular frequency (in rad/s). At a specific reverse bias voltage , the power factor of the equivalent AC circuit, as seen by the internal photo-current source, becomes unity. Which of the following expressions correctly gives ?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Photo-diode vs LED Bias|Driven Oscillations and Resonance|Power Factor Definition
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to correctly model an internal source in an AC circuit and apply the fundamental definition of power factor.
The primary trap lies in the visual 'series' connection of the external inductor and resistor to the diode terminals.
Students commonly misapply the series resonance condition () without realizing that the photo-diode's internal current generation acts as a Norton equivalent source in parallel with its junction capacitance.
Consequently, the resonance (unity power factor) is a parallel tank circuit phenomenon, requiring the cancellation of the imaginary part of the total admittance, not the series impedance.
This highlights the difference between external voltage driving and internal current driving in semiconductor devices.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Semiconductor Electronics: Materials, Devices, and Simple Circuits - Class 12 |
| Concept | Photo-diode vs LED Bias |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |