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Question #43436

Difficulty: 8/10 | 🟢 Free

The Question

A rigid, non-conducting circular ring of radius RR is placed coaxially inside a long solenoid. The solenoid produces a uniform magnetic field B0k^B_0 \hat{k} along its axis (the zz-axis). Additionally, a long straight wire carrying a constant current II is placed exactly along the zz-axis. An electron of mass mem_e and charge −e-e is constrained to move without friction on the ring. Initially, the ring is deep inside the solenoid, and the electron revolves with an angular velocity ω⃗0=ω0k^\vec{\omega}_0 = \omega_0 \hat{k}. The ring is then slowly translated along the zz-axis to a region far outside the solenoid where the solenoid's magnetic field is negligible. The long straight wire extends infinitely and its field remains present throughout. What is the final angular velocity ω⃗f\vec{\omega}_f of the electron?

Options

  • A.

    (ω0−eB02me)k^\left( \omega_0 - \frac{e B_0}{2m_e} \right) \hat{k}

  • B.

    (ω0+eB02me)k^\left( \omega_0 + \frac{e B_0}{2m_e} \right) \hat{k}

  • C.

    (ω0−eB02me−eμ0I4πmeR)k^\left( \omega_0 - \frac{e B_0}{2m_e} - \frac{e \mu_0 I}{4\pi m_e R} \right) \hat{k}

  • D.

    \omega_0 \hat{k}

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Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Magnetic Dipole Moment of Revolving Electron|Superposition of Magnetic Fields|Solenoid Fringe Fields

Why This Question Is Tricky

Common Mistakes

This question tests the application of the Superposition Principle and the dynamics of charged particles in non-uniform magnetic fields.

A common trap is assuming the mechanical angular momentum or magnetic dipole moment is strictly conserved (yielding ωf=ω0\omega_f = \omega_0), ignoring the azimuthal Lorentz force exerted by the solenoid's radial fringe field (BrB_r) during translation.

Furthermore, students may incorrectly assume the magnetic field from the straight wire (B⃗∝θ^\vec{B} \propto \hat{\theta}) alters the angular velocity.

However, the cross product of the translation velocity (vzk^v_z \hat{k}) and the azimuthal field yields a purely radial force, which is neutralized by the rigid ring and produces no torque, making the straight wire a conceptual distractor.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMagnetism and Matter - Class 12
ConceptMagnetic Dipole Moment of Revolving Electron
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree