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Question #43410

Difficulty: 8/10 | 🟢 Free

The Question

A hypothetical 'atomic galvanometer' is constructed using a single Hydrogen atom (Z=1Z=1). The 'coil' of this galvanometer is the single electron orbiting in the nthn^{\text{th}} Bohr orbit. The atom is placed in a uniform radial magnetic field BB such that the plane of the electron's orbit is always parallel to the magnetic field lines. A microscopic restoring mechanism provides a restoring torque τ=−kθ\tau = -k \theta, where θ\theta is the angular deflection of the orbital plane and kk is the torsional constant. If the torsional constant is given by k=∣En∣πk = \frac{|E_n|}{\pi}, where EnE_n is the total mechanical energy of the electron in the nthn^{\text{th}} orbit, what is the magnitude of the magnetic field BB required to produce a steady deflection of θ=π\theta = \pi radians?

(Given: mem_e is the mass of the electron, ee is the elementary charge, ℏ\hbar is the reduced Planck's constant, and ϵ0\epsilon_0 is the vacuum permittivity. Assume the magnetic field does not alter the Bohr orbit.)

Options

  • A.

    me2e316π2ϵ02ℏ3n3\frac{m_e^2 e^3}{16 \pi^2 \epsilon_0^2 \hbar^3 n^3}

  • B.

    me2e316π2ϵ02ℏ3n4\frac{m_e^2 e^3}{16 \pi^2 \epsilon_0^2 \hbar^3 n^4}

  • C.

    me2e332π2ϵ02ℏ3n3\frac{m_e^2 e^3}{32 \pi^2 \epsilon_0^2 \hbar^3 n^3}

  • D.

    me2e38π2ϵ02ℏ3n2\frac{m_e^2 e^3}{8 \pi^2 \epsilon_0^2 \hbar^3 n^2}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Galvanometer Sensitivity Logic|Magnetic Moment of Orbiting Electron|Quantization of Angular Momentum

Why This Question Is Tricky

Common Mistakes

This question tests the synthesis of classical electrodynamics (galvanometer sensitivity) with quantum mechanical constraints (Bohr model).

The primary trap lies in the misinterpretation of the 'number of turns' NN in the macroscopic torque equation τ=NIAB\tau = NIAB.

Students often erroneously substitute the principal quantum number nn for NN, assuming the nthn^{\text{th}} orbit acts as an nn-turn coil, leading to an incorrect n4n^4 dependence in the denominator (Option B).

Furthermore, it challenges students to recall the exact relation between orbital angular momentum and magnetic moment (μ=e2meL\mu = \frac{e}{2m_e}L) without defaulting to classical current derivations that often drop the 1/21/2 factor (Option C), ensuring a rigorous check of both conceptual bridging and algebraic precision.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMoving Charges and Magnetism - Class 12
ConceptGalvanometer Sensitivity Logic
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree