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Question #43401

Difficulty: 8/10 | 🟢 Free

The Question

A particle of mass mm and charge qq moves in an elliptical orbit around a fixed heavy nucleus located at one of the foci. The semi-major and semi-minor axes of the orbit are aa and bb respectively, and the period of revolution is TT. Which of the following expressions represents the magnitude of the time-averaged magnetic field ⟨B⟩\langle B \rangle produced by the orbiting charge at the nucleus?

Options

  • A.

    μ0qa2Tb2\frac{\mu_0 q a}{2 T b^2}

  • B.

    μ0q2Tab\frac{\mu_0 q}{2 T \sqrt{ab}}

  • C.

    μ0qb2Ta2\frac{\mu_0 q b}{2 T a^2}

  • D.

    μ0q2Ta\frac{\mu_0 q}{2 T a}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Magnetic Field on Axis vs. Center|Kepler’s Second Law|Integration

Why This Question Is Tricky

Common Mistakes

This problem tests the synthesis of electromagnetism and classical orbital mechanics.

A common trap is to treat the elliptical orbit as an equivalent circular current loop of radius R=abR = \sqrt{ab} (matching the area) or R=aR = a, which incorrectly assumes a constant angular velocity and uniform distance.

Students often fail to recognize that the instantaneous magnetic field depends on 1/r21/r^2 while the angular velocity also depends on 1/r21/r^2, making the time-average heavily weighted towards the periapsis.

By applying Kepler's Second Law (dt∝r2dθdt \propto r^2 d\theta), the r3r^3 term in the Biot-Savart denominator partially cancels, transforming the time integral into a purely geometric angular integral of 1/r1/r.

This elegantly avoids the need for complex time-dependent parameterizations and exposes the fallacy of the circular loop approximation.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMoving Charges and Magnetism - Class 12
ConceptMagnetic Field on Axis vs. Center
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree