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Question #43397
The Question
A straight wire of finite length is placed along the -axis from to . It carries a time-varying current , where is a positive constant. Assuming the quasi-static approximation is valid and that the electric field vanishes at infinity, what is the magnitude of the non-conservative induced electric field (ignoring any electrostatic contributions from charge accumulation at the ends) at a point located on the perpendicular bisector of the wire at a distance from its center?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Infinite Wire vs. Finite Wire|Induced Electric Fields|Vector Cross-Products
Why This Question Is Tricky
Common Mistakes
The problem tests the application of Faraday's Law in integral form for a dynamic induction scenario.
A common trap is assuming the magnetic field of an infinite wire () can be used.
However, integrating the infinite wire field to infinity yields a divergent flux, making the induced electric field undefined.
Students must recognize that the finite length of the wire is physically necessary to compute a finite flux linkage.
They must apply the Biot-Savart law for a finite wire and integrate the non-uniform, time-varying flux over a semi-infinite strip to correctly determine the induced electric field.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Moving Charges and Magnetism - Class 12 |
| Concept | Infinite Wire vs. Finite Wire |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |