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Question #43392

Difficulty: 8/10 | 🟢 Free

The Question

A long straight solid cylindrical conductor of radius RR carries a steady current. The current density J⃗\vec{J} is parallel to the axis of the cylinder and its magnitude varies with the radial distance rr from the axis as J(r)=J0(rR)J(r) = J_0 \left(\frac{r}{R}\right), where J0J_0 is a positive constant. Let B1B_1 be the magnitude of the magnetic field at a radial distance r=R/2r = R/2 from the axis, and B2B_2 be the magnitude of the magnetic field at a radial distance r=2Rr = 2R from the axis. Which of the following correctly represents the pair (B1,B2)(B_1, B_2)?

Options

  • A.

    (μ0J0R12,μ0J0R6)\left( \frac{\mu_0 J_0 R}{12}, \frac{\mu_0 J_0 R}{6} \right)

  • B.

    (μ0J0R8,μ0J0R4)\left( \frac{\mu_0 J_0 R}{8}, \frac{\mu_0 J_0 R}{4} \right)

  • C.

    (μ0J0R16,μ0J0R8)\left( \frac{\mu_0 J_0 R}{16}, \frac{\mu_0 J_0 R}{8} \right)

  • D.

    (μ0J0R4,μ0J0R4)\left( \frac{\mu_0 J_0 R}{4}, \frac{\mu_0 J_0 R}{4} \right)

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Correct Answer

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Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Ampere’s Circuital Law Symmetry|Gauss Law Applicability|Integration (Radial)

Why This Question Is Tricky

Common Mistakes

This question tests the integral form of Ampere's Circuital Law, which is mathematically analogous to Gauss's Law for electrostatics.

The primary trap lies in how students calculate the enclosed current for a non-uniform distribution.

A common misconception is to simply multiply the local current density by the cross-sectional area (Ienc=J(r)×πr2I_{enc} = J(r) \times \pi r^2), which incorrectly yields B1=μ0J0R/8B_1 = \mu_0 J_0 R / 8 and B2=μ0J0R/4B_2 = \mu_0 J_0 R / 4.

To solve this correctly, students must recognize that the current density varies radially and set up the area integral Ienc=∫J⋅dAI_{enc} = \int J \cdot dA using the differential area element of a ring, dA=2πrdrdA = 2\pi r dr.

Failing to account for this variable cross-sectional area weighting leads to incorrect polynomial dependencies and wrong coefficients.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMoving Charges and Magnetism - Class 12
ConceptAmpere’s Circuital Law Symmetry
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree