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Question #43389

Difficulty: 8/10 | 🟢 Free

The Question

A particle of mass mm and charge qq is projected with an initial speed v0v_0 in a vertical plane (assume gravity is negligible). A uniform horizontal magnetic field of magnitude BB exists perpendicular to this plane. The region contains a viscous medium that exerts a drag force F⃗d=−kv⃗\vec{F}_d = -k\vec{v} on the particle, where kk is a positive constant and v⃗\vec{v} is the instantaneous velocity. Which of the following expressions correctly gives the total distance SS traveled by the particle before coming to rest, and the radius of curvature RR of its path when its velocity vector has rotated by an angle θ\theta from its initial direction?

Options

  • A.

    S=mv0kS = \frac{mv_0}{k}, R=mv0qBe−kθqBR = \frac{mv_0}{qB} e^{-\frac{k\theta}{qB}}

  • B.

    S=mv0qBS = \frac{mv_0}{qB}, R=mv0ke−qBθkR = \frac{mv_0}{k} e^{-\frac{qB\theta}{k}}

  • C.

    S=mv0kS = \frac{mv_0}{k}, R=mv0qBe−qBθkR = \frac{mv_0}{qB} e^{-\frac{qB\theta}{k}}

  • D.

    S=mv0ke−kθqBS = \frac{mv_0}{k} e^{-\frac{k\theta}{qB}}, R=mv0qBR = \frac{mv_0}{qB}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Cyclotron Frequency Invariance|Vertical Circular Motion|Integration

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to decouple orthogonal forces in a non-conservative system.

A common trap is assuming that because the speed decays, the angular velocity or orbital period must also change.

Students often misapply the relation T=2πR/vT = 2\pi R/v, thinking that a decreasing radius implies a changing period, failing to realize that RR and vv decay proportionally.

By separating the tangential equation (which yields v(t)=v0e−(k/m)tv(t) = v_0 e^{-(k/m)t}) from the normal equation (which yields a constant ω=qB/m\omega = qB/m), students can map the time domain to the angular domain to find the exact geometric properties of the logarithmic spiral trajectory.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMoving Charges and Magnetism - Class 12
ConceptCyclotron Frequency Invariance
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree