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Question #43385

Difficulty: 8/10 | 🟢 Free

The Question

A particle of mass mm and charge q>0q > 0 is initially moving in a circular orbit of radius r0r_0 with speed v0v_0 in a uniform magnetic field B0B_0. The magnetic field is directed perpendicular to the plane of the orbit. The magnetic field is slowly increased to 4B04B_0 over a time interval TT (where TT is much larger than the time period of the orbit). Let L0=mv0r0L_0 = m v_0 r_0 and K0=12mv02K_0 = \frac{1}{2} m v_0^2 be the initial angular momentum and kinetic energy of the particle. Which of the following represents the magnitude of the final angular momentum LfL_f and final kinetic energy KfK_f of the particle?

Options

  • A.

    Lf=L0L_f = L_0, Kf=4K0K_f = 4 K_0

  • B.

    Lf=4L0L_f = 4 L_0, Kf=16K0K_f = 16 K_0

  • C.

    Lf=14L0L_f = \frac{1}{4} L_0, Kf=K0K_f = K_0

  • D.

    Lf=2L0L_f = 2 L_0, Kf=4K0K_f = 4 K_0

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Cyclotron Frequency Invariance|Angular Momentum conservation|Vector Cross-Products

Why This Question Is Tricky

Common Mistakes

This question tests the misconception that an induced electric field in a time-varying magnetic field must change the mechanical angular momentum of a charged particle.

Students often calculate the torque due to the induced electric field (τE=qrEθ\tau_E = q r E_\theta) but completely ignore the torque from the magnetic field (τB=−qrvrB\tau_B = -q r v_r B) that arises because the orbit radius is shrinking (vr≠0v_r \neq 0).

In an adiabatic process, these two torques exactly cancel, conserving mechanical angular momentum, even though the kinetic energy increases due to the work done by the non-conservative electric field.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMoving Charges and Magnetism - Class 12
ConceptCyclotron Frequency Invariance
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree