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Question #43372

Difficulty: 8/10 | 🟢 Free

The Question

A potentiometer wire ABAB of length L=1.0 mL = 1.0 \text{ m} and uniform cross-sectional area AA is connected to a primary ideal cell of electromotive force E0=16 VE_0 = 16 \text{ V} and zero internal resistance. The wire ABAB is subjected to a non-uniform temperature distribution along its length given by T(x)=T0+ΔT(xL)2T(x) = T_0 + \Delta T \left(\frac{x}{L}\right)^2, where xx is the distance from end AA. The resistivity of the wire varies with temperature as ρ(T)=ρ0[1+α(T−T0)]\rho(T) = \rho_0 [1 + \alpha(T - T_0)]. Given that the product of the temperature coefficient of resistivity α\alpha and ΔT\Delta T is αΔT=3.0\alpha \Delta T = 3.0. A secondary cell of electromotive force E1=5.0 VE_1 = 5.0 \text{ V} and internal resistance r=1.0 Ωr = 1.0 \ \Omega is connected to a galvanometer to find the null point on the wire ABAB. Find the distance xx from end AA where the galvanometer shows zero deflection.

Options

  • A.

    0.50 m0.50 \text{ m}

  • B.

    0.31 m0.31 \text{ m}

  • C.

    0.60 m0.60 \text{ m}

  • D.

    0.46 m0.46 \text{ m}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Temperature Coefficient (Alpha)|Potentiometer Null Point|Resistivity vs Resistance

Why This Question Is Tricky

Common Mistakes

The core trap lies in the assumption that resistance (and thus potential drop) scales linearly with length (V∝LV \propto L), which is only true for isothermal, uniform wires.

Students often memorize the standard potentiometer formula V=(E/L)xV = (E/L)x and blindly apply it, leading to the incorrect answer of 0.31 m0.31 \text{ m}.

A secondary trap occurs if a student correctly identifies that resistivity changes but incorrectly calculates resistance algebraically as R(x)=ρ(x)xAR(x) = \rho(x) \frac{x}{A} instead of integrating the local resistivity ∫ρ(x)dx/A\int \rho(x) dx / A, leading to 0.60 m0.60 \text{ m}.

This problem rigorously tests the differential definition of resistance and its integration over a spatial thermal gradient.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterCurrent Electricity - Class 12
ConceptTemperature Coefficient (Alpha)
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree