Before You Begin
Question #43354
The Question
Three concentric thin conducting spherical shells of radii , , and are arranged in a vacuum. The innermost shell is grounded. The middle shell is given a charge and the outermost shell is given a charge . The potential difference between the middle and outermost shells is connected across a secondary circuit to find its null point on a potentiometer. The potentiometer consists of a uniform wire of length and resistance , driven by a primary ideal battery of EMF and a series resistance of . If the null point is obtained at a distance from the high-potential end of the potentiometer wire, what is the value of ? (Assume the secondary circuit draws no current at the null point and ).
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Multi-Concept_Bridge
Master problems that require linking physics and math concepts to solve complex competitive questions.
Concepts Behind This Question
Potentiometer Null Point|Potential of Concentric Shells|Vector Cross-Products
Why This Question Is Tricky
Common Mistakes
This question tests the student's understanding of electrostatic shielding, grounding, and the superposition principle in concentric shell geometries.
A common lethal mistake is assuming that an uncharged inner shell remains uncharged when grounded because it is 'shielded' by the outer shells.
Students falling for this trap will ignore the induced charge () and incorrectly calculate the electric field in the region between the middle and outer shells based solely on the middle shell's charge .
This leads to an incorrect potential difference and the trap answer.
A secondary trap involves neglecting the series resistance in the primary potentiometer circuit when calculating the potential gradient.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Current Electricity - Class 12 |
| Concept | Potentiometer Null Point |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |