Start Learning Free

Before You Begin

Question #43350

Difficulty: 8/10 | 🟢 Free

The Question

Consider a Wheatstone bridge circuit powered by an ideal DC voltage source V0V_0. The left branch consists of a temperature-independent resistor RR in series with a p-n junction diode DD (connected to ground). The right branch consists of two temperature-independent resistors, RR and RvR_v. The output voltage is measured between the midpoints: Vout=Vright−VleftV_{out} = V_{right} - V_{left}, where VleftV_{left} is the voltage across the diode.

The diode operates in the forward-bias region with current I=Is(T)eqVD/kTI = I_s(T) e^{qV_D/kT}, where VDV_D is the diode voltage, qq is the elementary charge, and kk is the Boltzmann constant. The reverse saturation current depends on absolute temperature TT as Is(T)=CT3e−Eg/kTI_s(T) = C T^3 e^{-E_g/kT}, where CC is a material constant and EgE_g is the bandgap energy.

At a specific temperature TT, the bridge is balanced (Vout=0V_{out} = 0) by adjusting RvR_v. At this operating point, the diode has a dynamic resistance rd=kTqIr_d = \frac{kT}{qI}. Determine the temperature sensitivity of the bridge, defined as S=dVoutdTS = \frac{dV_{out}}{dT}, at this balanced state.

Options

  • A.

    Eg/q+3kT/q−VDT(1+rd/R)\frac{E_g/q + 3kT/q - V_D}{T(1 + r_d/R)}

  • B.

    Eg/q−VDT(1+rd/R)\frac{E_g/q - V_D}{T(1 + r_d/R)}

  • C.

    Eg/q+3kT/q−VDT\frac{E_g/q + 3kT/q - V_D}{T}

  • D.

    VD−Eg/q−3kT/qT(1+R/rd)\frac{V_D - E_g/q - 3kT/q}{T(1 + R/r_d)}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Wheatstone Bridge Sensitivity|Load Line Analysis|Exponential Approximations

Why This Question Is Tricky

Common Mistakes

This question tests the integration of non-linear load line analysis with semiconductor thermodynamics.

The primary trap lies in treating the diode current as constant during temperature variations.

Students often calculate the sensitivity by taking the partial derivative of the diode equation with respect to temperature, ignoring the implicit shift in the operating point along the load line (KVL constraint V0=IR+VDV_0 = IR + V_D).

This omission leads to missing the (1+rd/R)(1 + r_d/R) attenuation factor (Option C).

A secondary trap is neglecting the T3T^3 dependence of the saturation current IsI_s, which arises from the temperature dependence of the effective density of states and thermal velocity, leading to the omission of the 3kT/q3kT/q term (Option B).

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterCurrent Electricity - Class 12
ConceptWheatstone Bridge Sensitivity
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree