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Question #43347
The Question
An circuit consists of a capacitor of capacitance initially charged to a voltage , an ideal inductor of inductance , and a thermally insulated resistor. The initial resistance of the resistor is . As the circuit oscillates, the resistor heats up due to Joule heating. The resistance varies with the total heat energy dissipated in it according to the relation , where is a positive constant. It is given that if the entire initial stored energy of the capacitor were to be dissipated in the resistor, its resistance would become . Assuming the circuit is highly underdamped () such that the fractional energy loss per cycle is negligible, find the time taken for the total electromagnetic energy of the circuit to reduce to half of its initial value.
Options
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Variable_Constraint
Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.
Concepts Behind This Question
LC Oscillations Energy Cycle|Quality Factor (Q-factor)|Internal Resistance Variation
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to couple energy conservation with a non-linear dissipation mechanism.
The primary trap is assuming the Quality factor (and thus the damping coefficient) remains constant, leading students to blindly apply the standard exponential decay formula .
By making the internal resistance a function of the dissipated Joule heat, the linear ODE transforms into a logistic-type differential equation.
Students must recognize that the instantaneous rate of energy loss depends on the current energy state, requiring first-principles integration rather than memorized formulas.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Alternating Current - Class 12 |
| Concept | LC Oscillations Energy Cycle |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |