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Question #43341

Difficulty: 8/10 | 🟢 Free

The Question

A series LCR circuit with a quality factor Q=50Q = 50 and resonant frequency ω0=1000 rad s−1\omega_0 = 1000 \text{ rad s}^{-1} is connected to an alternating voltage source V(t)=V0cos⁡(ω0t)V(t) = V_0 \cos(\omega_0 t) at time t=0t=0. The initial charge on the capacitor and the initial current in the inductor are both zero. Assuming the circuit is highly underdamped (Q≫1Q \gg 1), the total current in the circuit can be approximated as an oscillating function with a time-varying amplitude I(t)I(t). Find the time t0t_0 at which the amplitude I(t)I(t) reaches (1−e−1)(1 - e^{-1}) of its final steady-state value.

Options

  • A.

    0.10 s0.10 \text{ s}

  • B.

    0.05 s0.05 \text{ s}

  • C.

    0.02 s0.02 \text{ s}

  • D.

    0.20 s0.20 \text{ s}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Bandwidth in RLC|Series LCR Impedance Vector|Transient Current in RL Circuit|Differential Equations

Why This Question Is Tricky

Common Mistakes

This question tests the student's understanding of transient dynamics in an AC-driven LCR circuit, specifically targeting a common misconception regarding time constants.

Students frequently confuse the time constant of a simple RL circuit (τ=L/R\tau = L/R) with the amplitude decay time constant of an underdamped second-order LCR circuit.

Because the characteristic equation of the LCR circuit yields a real part of −R/2L-R/2L, the transient amplitude envelope decays as e−Rt/2Le^{-Rt/2L}, making the true time constant τ=2L/R\tau = 2L/R.

A student who blindly applies the steady-state bandwidth formula (Δω=R/L\Delta \omega = R/L) and assumes the transient envelope decays as e−(Δω)te^{-(\Delta \omega) t} will incorrectly choose 0.05 s0.05 \text{ s}.

This highlights the critical distinction between energy decay rate (proportional to e−Rt/Le^{-Rt/L}) and amplitude decay rate (proportional to e−Rt/2Le^{-Rt/2L}).

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterAlternating Current - Class 12
ConceptBandwidth in RLC
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree