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Question #43322

Difficulty: 8/10 | 🟢 Free

The Question

Consider an LC circuit with an ideal inductor of inductance LL and a non-linear capacitor. The potential difference VV across the capacitor is related to the charge qq on its plates by V(q)=qC0−βq3V(q) = \frac{q}{C_0} - \beta q^3, where C0C_0 and β\beta are positive constants, and β\beta is sufficiently small such that βC0q2≪1\beta C_0 q^2 \ll 1. The circuit oscillates with a maximum charge q0q_0 on the capacitor. By mapping this system to an analogous mechanical oscillator (where charge qq corresponds to angular displacement θ\theta, and LL corresponds to moment of inertia II), one can analyze its anharmonic behavior similar to a large-angle physical pendulum. Let T0=2πLC0T_0 = 2\pi\sqrt{LC_0} be the period of the linear system (where β=0\beta = 0). Which of the following gives the fractional change in the time period ΔTT0=T−T0T0\frac{\Delta T}{T_0} = \frac{T - T_0}{T_0} to the first order in β\beta, and correctly identifies the geometric feature of the potential energy U(q)U(q) curve responsible for this change?

Options

  • A.

    38βC0q02\frac{3}{8} \beta C_0 q_0^2 ; U(q)U(q) is less concave upwards than a parabola, meaning the effective restoring 'torque' is weaker.

  • B.

    −38βC0q02-\frac{3}{8} \beta C_0 q_0^2 ; U(q)U(q) is more concave upwards than a parabola, meaning the effective restoring 'torque' is stronger.

  • C.

    34βC0q02\frac{3}{4} \beta C_0 q_0^2 ; U(q)U(q) is less concave upwards than a parabola, meaning the effective restoring 'torque' is weaker.

  • D.

    14βC0q02\frac{1}{4} \beta C_0 q_0^2 ; U(q)U(q) is less concave upwards than a parabola, meaning the effective restoring 'torque' is weaker.

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

LC Circuit Oscillations|Compound Pendulum Period|Graphical Concavity Significance

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to map an electrical LC circuit to a mechanical anharmonic oscillator (like a large-angle physical pendulum) and analyze the effect of non-linear restoring forces on the time period.

A common trap is assuming that any non-linear term simply scales the period linearly without properly evaluating the elliptic integral approximation, leading to incorrect coefficients like 3/4 (if the 1/2 from the binomial expansion is missed) or 1/4 (if the angular dependence in the integral is ignored).

Furthermore, students often misinterpret the physical meaning of the potential energy graph's concavity; a negative higher-order term in the restoring force makes the U(q) curve less concave upwards (flatter), which physically corresponds to a weaker average restoring force and consequently a longer time period.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectromagnetic Induction - Class 12
ConceptLC Circuit Oscillations
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree