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Question #43318
The Question
An ideal capacitor of capacitance is initially charged to a voltage . At time , it is connected in a closed series loop with an inductor of inductance and a time-varying resistor. The resistance of the resistor increases linearly with time as , where is a positive constant in . Assume that the circuit remains highly underdamped during the time interval of interest (i.e., the fractional energy loss per cycle is very small). Which of the following expressions gives the time at which the total electromagnetic energy of the circuit decreases to of its initial value?
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Multi-Concept_Bridge
Master problems that require linking physics and math concepts to solve complex competitive questions.
Concepts Behind This Question
LC Circuit Oscillations|Internal Resistance Variation|Differential Equations
Why This Question Is Tricky
Common Mistakes
This question tests the student's ability to analyze non-autonomous dissipative systems, specifically an LC circuit with a time-varying internal resistance.
The primary trap is the premature assumption of an invariant decay constant.
Students often memorize the energy decay formula for a constant resistance, , and incorrectly substitute directly into the exponent to get .
This leads to the incorrect answer .
By doing so, they bypass the fundamental principle of energy conservation () and fail to integrate the time-varying damping factor, missing the crucial factor of that arises from the integration of with respect to time.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Electromagnetic Induction - Class 12 |
| Concept | LC Circuit Oscillations |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |