Start Learning Free

Before You Begin

Question #43310

Difficulty: 8/10 | 🟢 Free

The Question

Two rigid, arbitrarily shaped conducting loops, L1L_1 and L2L_2, are placed in a vacuum. L1L_1 is fixed and carries a constant current I1=5 AI_1 = 5 \text{ A}. L2L_2 has a resistance R=2 ΩR = 2 \ \Omega and is initially at infinity. In Process I, L2L_2 is moved quasi-statically to a final position PP, requiring external work WIW_I against magnetic forces. In Process II, L2L_2 is moved rapidly to the same position PP along the identical path, generating an entropy increase ΔS>0\Delta S > 0 due to Joule heating, and requiring external work WIIW_{II} against magnetic forces. Let M12M_{12} be the magnetic flux through L1L_1 per unit current in L2L_2, and M21M_{21} be the magnetic flux through L2L_2 per unit current in L1L_1, evaluated at position PP after Process II. Which of the following relationships is correct?

Options

  • A.

    M12=M21,  WII>WIM_{12} = M_{21}, \; W_{II} > W_{I}

  • B.

    M12≠M21,  WII>WIM_{12} \neq M_{21}, \; W_{II} > W_{I}

  • C.

    M12=M21,  WII=WIM_{12} = M_{21}, \; W_{II} = W_{I}

  • D.

    M12≠M21,  WII=WIM_{12} \neq M_{21}, \; W_{II} = W_{I}

Check Your Answer

Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Mutual Inductance Reciprocity|Motional EMF for Arbitrary Shapes|Entropy and Reversibility|Thermodynamic Work

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to distinguish between purely geometric electromagnetic properties and path-dependent thermodynamic quantities.

A common trap is assuming that the reciprocity theorem (M12=M21M_{12} = M_{21}) relies on thermodynamic reversibility, leading students to incorrectly conclude that time-asymmetric entropy generation (Joule heating) breaks this symmetry.

Furthermore, students often misapply the concept of conservative fields to magnetic forces, incorrectly assuming the work done moving a coil in a magnetic field is independent of the rate of motion (WII=WIW_{II} = W_I).

By recognizing that mutual inductance is governed by Neumann's geometric formula and that motional EMF induces velocity-dependent non-conservative drag forces, the correct relationship is established.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterElectromagnetic Induction - Class 12
ConceptMutual Inductance Reciprocity
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree