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Question #43287

Difficulty: 8/10 | 🟢 Free

The Question

A thin rectangular plate of mass 2m2m, length LL (spanning 0≤x≤L0 \le x \le L), width 2a2a (spanning −a≤y≤a-a \le y \le a), and uniform thickness tt has a non-uniform magnetization given by M⃗=M0(xLi^+yaj^)\vec{M} = M_0 \left( \frac{x}{L} \hat{i} + \frac{y}{a} \hat{j} \right). The plate is cut into two pieces along the diagonal line connecting (0,−a)(0, -a) and (L,a)(L, a). The upper fragment (the piece containing the point (0,a)(0, a)) is taken and reshaped into a uniform solid sphere of mass mm and radius RR. During this reshaping, its total magnetic dipole moment vector μ⃗\vec{\mu} is preserved and becomes permanently fixed relative to the sphere's material. The sphere is placed in free space and is initially at rest. A short magnetic field pulse B⃗(t)=Bpδ(t)k^\vec{B}(t) = B_p \delta(t) \hat{k} is applied, where δ(t)\delta(t) is the Dirac delta function. Find the magnitude of the angular velocity of the sphere immediately after the pulse.

Options

  • A.

    52M0aLtBp6mR2\frac{5 \sqrt{2} M_0 a L t B_p}{6 m R^2}

  • B.

    5M0aLtBp4mR2\frac{5 M_0 a L t B_p}{4 m R^2}

  • C.

    5M0aLtBp6mR2\frac{5 M_0 a L t B_p}{6 m R^2}

  • D.

    5M0aLtBp2mR2\frac{5 M_0 a L t B_p}{2 m R^2}

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How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Effective Moment of Cut Magnets|Magnetic Dipole Moment of Revolving Electron|Integration

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to calculate the magnetic dipole moment of an extended body with non-uniform magnetization and apply the angular impulse-momentum theorem.

The primary trap lies in the assumption that the dipole moment of a cut fragment retains the direction of the original magnet's axis or aligns with the cut geometry.

By defining a spatially varying magnetization M⃗(x,y)\vec{M}(x,y), students are forced to perform a rigorous volume integral μ⃗=∫M⃗dV\vec{\mu} = \int \vec{M} dV over a triangular domain.

A common mistake is to either assume μ⃗\vec{\mu} is purely along the x-axis (yielding an incorrect torque magnitude) or to incorrectly average the magnetization.

Furthermore, applying the cross-product τ⃗=μ⃗×B⃗\vec{\tau} = \vec{\mu} \times \vec{B} with a Dirac delta magnetic field tests the conceptual link between impulsive torque and instantaneous change in angular momentum.

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Question Information

SubjectPhysics
ChapterMagnetism and Matter - Class 12
ConceptEffective Moment of Cut Magnets
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree