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Question #43285

Difficulty: 8/10 | 🟢 Free

The Question

A long straight wire carrying a steady current I=50 AI = 50 \text{ A} lies along the zz-axis. It is surrounded by a non-homogeneous paramagnetic cylindrical shell of inner radius a=0.1 ma = 0.1 \text{ m} and outer radius b=0.2 mb = 0.2 \text{ m}. The magnetic susceptibility of the shell varies radially as χm(r)=kr\chi_m(r) = k r, where k=20 m−1k = 20 \text{ m}^{-1} and rr is the perpendicular distance from the zz-axis. Calculate the total magnetic flux Φ\Phi passing through a rectangular cross-section of the shell of length L=2.0 mL = 2.0 \text{ m} parallel to the zz-axis. (Assume the permeability of free space is μ0=4π×10−7 T⋅m/A\mu_0 = 4\pi \times 10^{-7} \text{ T}\cdot\text{m/A}).

Options

  • A.

    20(ln⁡2+2) \muWb20 (\ln 2 + 2) \text{ \mu Wb}

  • B.

    80ln⁡2 \muWb80 \ln 2 \text{ \mu Wb}

  • C.

    60ln⁡2 \muWb60 \ln 2 \text{ \mu Wb}

  • D.

    100ln⁡2 \muWb100 \ln 2 \text{ \mu Wb}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Magnetic Field Line Behavior in Matter|Magnetic Permeability and Susceptibility|Continuous Charge Distribution|Integration

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to apply magnetic field relations locally in a non-homogeneous medium.

A common trap in JEE preparation is treating magnetic permeability μ\mu as a macroscopic constant and pulling it out of the flux integral, often by calculating an 'average' susceptibility (e.g., χavg=20×0.15=3\chi_{avg} = 20 \times 0.15 = 3, leading to the incorrect 80ln⁡2 \muWb80 \ln 2 \text{ \mu Wb}).

By defining χm\chi_m as a function of rr, the problem forces the application of the differential form of the constitutive relation B=μ0(H+M)\mathbf{B} = \mu_0(\mathbf{H} + \mathbf{M}) before integrating over the area.

It highlights that the bound volume current density Jb=∇×M\mathbf{J}_b = \nabla \times \mathbf{M} continuously modifies the local magnetic field, invalidating lumped-parameter approaches.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMagnetism and Matter - Class 12
ConceptMagnetic Field Line Behavior in Matter
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree