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Question #43257

Difficulty: 8/10 | 🟢 Free

The Question

An electron of mass mm (in kg) and charge −e-e (in C) orbits a massive nucleus in an elliptical orbit. The orbit has a semi-major axis aa (in m), eccentricity ϵ\epsilon (dimensionless), and time period TT (in s). The nucleus is located at one of the foci of the ellipse. What is the magnitude of the instantaneous magnetic field BB (in T) produced by the electron at the nucleus when the electron is at its apocenter (farthest point from the nucleus)? Assume non-relativistic motion and vacuum permeability μ0\mu_0 (in T⋅m/A\text{T}\cdot\text{m/A}).

Options

  • A.

    μ0e2aT1−ϵ(1+ϵ)5/2\frac{\mu_0 e}{2 a T} \frac{\sqrt{1-\epsilon}}{(1+\epsilon)^{5/2}}

  • B.

    μ0e2aT11+ϵ\frac{\mu_0 e}{2 a T} \frac{1}{1+\epsilon}

  • C.

    μ0e2aT1(1+ϵ)2\frac{\mu_0 e}{2 a T} \frac{1}{(1+\epsilon)^2}

  • D.

    μ0e2aT1−ϵ1+ϵ\frac{\mu_0 e}{2 a T} \sqrt{\frac{1-\epsilon}{1+\epsilon}}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Magnetic Dipole Moment of Revolving Electron|Kepler’s Second Law (Areal Velocity)|Vector Cross-Product

Why This Question Is Tricky

Common Mistakes

This question tests the misapplication of the average current formula I=q/TI = q/T to calculate instantaneous magnetic fields in non-circular orbits.

Students often fall into the trap of assuming the electron acts as a steady circular current loop of radius r=a(1+ϵ)r = a(1+\epsilon), leading to the incorrect Biot-Savart application B=μ0I/(2r)B = \mu_0 I / (2r) (Option B).

Another common error is assuming a constant average orbital speed v=2πa/Tv = 2\pi a/T (Option C).

The correct physical framework requires recognizing that while the linear and angular velocities fluctuate, Kepler's Second Law dictates that the areal velocity remains constant.

This intrinsically links the instantaneous magnetic field to the conserved orbital angular momentum, demanding a derivation from fundamental point-charge electrodynamics rather than macroscopic steady-current approximations.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterMagnetism and Matter - Class 12
ConceptMagnetic Dipole Moment of Revolving Electron
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree