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Question #43238

Difficulty: 8/10 | 🟢 Free

The Question

A beam of electrons (rest mass m0m_0, charge −e-e) is accelerated from rest through a potential difference V=m0c2eV = \frac{m_0 c^2}{e}, where cc is the speed of light. The beam then passes through an electron-optical system consisting of two identical thin magnetic lenses separated by a distance dd. In electron optics, the optical power PP (reciprocal of focal length) of a thin magnetic lens is given by P=∫−∞∞(ωc2v)2dzP = \int_{-\infty}^{\infty} \left(\frac{\omega_c}{2v}\right)^2 dz, where vv is the speed of the electron and ωc\omega_c is the local cyclotron frequency of the electron in the axial magnetic field Bz(z)B_z(z). For each lens, the integral of the squared magnetic field is ∫−∞∞Bz2dz=β\int_{-\infty}^{\infty} B_z^2 dz = \beta. If the equivalent optical power of the two-lens system is zero (an afocal system), what is the required separation dd?

Options

  • A.

    24m02c2e2β\frac{24 m_0^2 c^2}{e^2 \beta}

  • B.

    6m02c2e2β\frac{6 m_0^2 c^2}{e^2 \beta}

  • C.

    16m02c2e2β\frac{16 m_0^2 c^2}{e^2 \beta}

  • D.

    8m02c2e2β\frac{8 m_0^2 c^2}{e^2 \beta}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Power Combination|Cyclotron Frequency Invariance|Trajectory of Charged Particle

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to apply relativistic corrections to electromagnetic phenomena, specifically the trajectory-dependent cyclotron frequency.

The primary trap lies in treating the cyclotron frequency as a non-relativistic invariant (ωc=eB/m0\omega_c = eB/m_0).

In the relativistic regime (v∼cv \sim c), the effective mass increases (γm0\gamma m_0), which decreases the cyclotron frequency and alters the focal length of the magnetic lens.

Students who fail to include the Lorentz factor γ\gamma in ωc\omega_c will incorrectly calculate the optical power, leading to Option B.

Additionally, students who incorrectly use classical kinetic energy (v2=2K/m0v^2 = 2K/m_0) will land on Option C.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterRay Optics and Optical Instruments - Class 12
ConceptPower Combination
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree