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Question #43237

Difficulty: 8/10 | 🟢 Free

The Question

A thin biconvex lens is placed in a temperature-controlled chamber. The chamber's temperature is monitored by a faulty thermometer that reads a scale XX. The relationship between the true Celsius temperature TCT_C and the faulty scale reading XX is given by TC=59(X−32)+190(X−32)2T_C = \frac{5}{9}(X - 32) + \frac{1}{90}(X - 32)^2, where TCT_C is in ∘C^\circ \text{C} and XX is in ∘X^\circ \text{X}. At a reading of X=62∘XX = 62^\circ \text{X}, the lens has an optical power P=+4.5 DP = +4.5 \text{ D}, a refractive index n=1.6n = 1.6, and a coefficient of linear thermal expansion α=2.0×10−5 ∘C−1\alpha = 2.0 \times 10^{-5} \text{ } ^\circ \text{C}^{-1}. The refractive index of the lens material varies with the true Celsius temperature at a rate of dndTC=−1.2×10−5 ∘C−1\frac{dn}{dT_C} = -1.2 \times 10^{-5} \text{ } ^\circ \text{C}^{-1}. What is the rate of change of the lens power with respect to the faulty temperature scale reading, dPdX\frac{dP}{dX}, at X=62∘XX = 62^\circ \text{X}?

Options

  • A.

    −2.2×10−4 D/∘X-2.2 \times 10^{-4} \text{ D/}^\circ \text{X}

  • B.

    −1.0×10−4 D/∘X-1.0 \times 10^{-4} \text{ D/}^\circ \text{X}

  • C.

    −1.1×10−4 D/∘X-1.1 \times 10^{-4} \text{ D/}^\circ \text{X}

  • D.

    −1.76×10−4 D/∘X-1.76 \times 10^{-4} \text{ D/}^\circ \text{X}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Power Combination|Thermal Properties of Matter|Latent Heat and Volume Change

Why This Question Is Tricky

Common Mistakes

This question tests the rigorous coupling of optical power dependencies with the differential mapping of a biased measuring device.

Students commonly fall into two traps: (1) misapplying the derivative of the Lens Maker's Formula by forgetting the 1/(n−1)1/(n-1) factor when substituting C=P/(n−1)C = P/(n-1), and (2) ignoring the non-linear term in the faulty thermometer's calibration curve, treating the conversion as a simple linear Fahrenheit-to-Celsius mapping.

By requiring the chain rule dPdX=dPdTCdTCdX\frac{dP}{dX} = \frac{dP}{dT_C} \frac{dT_C}{dX}, the problem ensures the student can synthesize geometric thermal expansion, refractive index temperature dependence, and non-linear scale calibration simultaneously.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterRay Optics and Optical Instruments - Class 12
ConceptPower Combination
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree