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Question #43234

Difficulty: 8/10 | 🟢 Free

The Question

A transparent right-angled prism ABC has ∠B=90∘\angle B = 90^\circ and ∠A=75∘\angle A = 75^\circ. Face AB is vertical, face BC is horizontal, and the refractive index of the prism is μp=2\mu_p = \sqrt{2}. Face AB is covered by an opaque screen containing a slit of width 2w=6 cm2w = 6 \text{ cm} (measured along AB). A converging beam of light in air is directed towards face AB such that its central ray is horizontal, passes exactly through the center of the slit, and is perpendicular to AB. In the absence of any other optical elements, the beam would converge to a virtual object OO located at a distance L0L_0 behind face AB.

A transparent dielectric slab of thickness t=6 cmt = 6 \text{ cm} and refractive index μs=1.5\mu_s = 1.5 is now placed in the path of the beam, parallel to face AB and in front of the slit. Determine the minimum value of L0L_0 such that all rays passing through the slit undergo total internal reflection (TIR) at face AC.

(Assume the longitudinal shift produced by the dielectric slab can be calculated using the paraxial approximation formula).

Options

  • A.

    1 cm1 \text{ cm}

  • B.

    3 cm3 \text{ cm}

  • C.

    5 cm5 \text{ cm}

  • D.

    2 cm2 \text{ cm}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Virtual Object Trap|Total Internal Reflection|Dielectric Slab Displacement

Why This Question Is Tricky

Common Mistakes

This question tests the interplay between longitudinal optical shift and aperture-limited angular spread.

A common trap is assuming that since a dielectric slab only produces a parallel shift, it does not affect the angle of incidence on the subsequent flat prism face.

However, the slit acts as an aperture stop; shifting the virtual object longitudinally changes the angle of the extreme rays that can physically pass through the slit (tan⁡α=w/L′\tan \alpha = w/L').

Students often either ignore the slab's shift entirely (yielding 3 cm), incorrectly subtract the shift instead of adding it to the virtual object distance (yielding 5 cm), or fail to correctly identify the geometry of the normal to the hypotenuse face, leading to incorrect TIR threshold conditions.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterRay Optics and Optical Instruments - Class 12
ConceptVirtual Object Trap
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree