Before You Begin
Question #43228
The Question
A compound microscope is constructed using an objective lens of focal length and an eyepiece of focal length . An object is placed at a distance of in front of the objective. To make the instrument compact, a right-angled glass prism of refractive index is inserted between the lenses to fold the light path via Total Internal Reflection. The physical length of the light path inside the glass prism is . If the final virtual image is formed at a distance of from the eyepiece, calculate the total physical path length of the central light ray between the objective and the eyepiece. (Assume paraxial rays and that the unfolded prism acts equivalently to a glass slab of thickness ).
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Microscope Tube Length|Total Internal Reflection (TIR)|Sign Convention Trap
Why This Question Is Tricky
Common Mistakes
This problem tests two critical JEE Advanced concepts: the effect of a dielectric medium on image position and the Gaussian sign convention for virtual images.
Students often fall into the 'Optical Path Length' trap by incorrectly using (adding optical path for phase) instead of the apparent depth shift , leading to the incorrect answer of .
Additionally, the 'Sign Convention Trap' catches students who substitute for the virtual image, yielding an incorrect eyepiece object distance of and a final answer of .
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Ray Optics and Optical Instruments - Class 12 |
| Concept | Microscope Tube Length |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |