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Question #43224

Difficulty: 8/10 | 🟢 Free

The Question

A laser beam is incident horizontally at the origin (0,0)(0,0) into a non-homogeneous transparent medium occupying the region x>0x > 0. The refractive index of the medium varies with height yy as n(y)=n01+αyn(y) = n_0 \sqrt{1 + \alpha y}, where n0n_0 is a dimensionless constant and α\alpha is a positive constant. The beam strikes a vertical screen placed at a horizontal distance x=L=(20.0±0.1) cmx = L = (20.0 \pm 0.1) \text{ cm}. The height yy of the laser spot on the screen is measured using a vertical scale with a least count of 0.01 cm0.01 \text{ cm}. The measured reading for the spot's height is 12.50 cm12.50 \text{ cm}. However, the scale has a known zero error of +10.50 cm+10.50 \text{ cm} (the scale reads 10.50 cm10.50 \text{ cm} when the actual height is zero). Calculate the value of the medium parameter α\alpha along with its absolute error Δα\Delta \alpha, in SI units (m−1\text{m}^{-1}). Assume the error in yy is solely due to the least count of the scale.

Options

  • A.

    (2.00±0.03) m−1(2.00 \pm 0.03) \text{ m}^{-1}

  • B.

    (12.50±0.14) m−1(12.50 \pm 0.14) \text{ m}^{-1}

  • C.

    (2.00±0.02) m−1(2.00 \pm 0.02) \text{ m}^{-1}

  • D.

    (23.00±0.24) m−1(23.00 \pm 0.24) \text{ m}^{-1}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Intuition_Breaker

Train your brain to resist "obvious" answers that are designed to deceive your intuition.

Concepts Behind This Question

Ray Tracing for Systems|Principle of Homogeneity Exceptions|Zero Error Correction in Instruments|Error Propagation

Why This Question Is Tricky

Common Mistakes

This question tests the synthesis of Fermat's principle (ray tracing in a non-homogeneous medium) with rigorous error analysis.

The primary trap lies in the zero-error correction.

Students often blindly plug the observed reading (12.50 cm12.50 \text{ cm}) into the trajectory equation, which drastically changes the physical parameter α\alpha.

Furthermore, the large zero error masks the true relative error; uncorrected, the relative error in yy appears to be 0.01/12.50≈0.08%0.01/12.50 \approx 0.08\%, but the true relative error is 0.01/2.00=0.5%0.01/2.00 = 0.5\%.

This evaluates the conceptual understanding that zero-error artifacts must be removed to find the physically significant value before applying the power rule for error propagation.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterRay Optics and Optical Instruments - Class 12
ConceptRay Tracing for Systems
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree