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Question #43223

Difficulty: 8/10 | 🟢 Free

The Question

A monochromatic plane wave of wavelength λ\lambda is incident normally on the flat base of a solid glass biprism of refractive index μ=3\mu = \sqrt{3}. The flat base has a total width of 2a2a. The slanted faces of the biprism make an angle α=30∘\alpha = 30^\circ with its flat base. The light refracted by the upper and lower halves of the biprism overlap to form an interference pattern. A viewing screen is placed perpendicular to the optical axis at a distance D=43aD = \frac{4}{3}a from the flat base (which lies within the region of beam overlap). What is the fringe width of the interference pattern observed on the screen?

Options

  • A.

    λ\lambda

  • B.

    43λ\frac{4}{3} \lambda

  • C.

    23λ\frac{2}{3} \lambda

  • D.

    3+34λ\frac{3+\sqrt{3}}{4} \lambda

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Ray Tracing for Systems|Phase Relationship|Fringe Width Invariance|Small Angle Approximation

Why This Question Is Tricky

Common Mistakes

This question tests the invariance of fringe width under geometric scaling and the breakdown of the paraxial approximation.

Students often blindly apply the standard YDSE formula β=λD/d\beta = \lambda D/d, treating DD as the distance to the screen and dd as some effective source separation (leading to distractors like 4λ/34\lambda/3 or 2λ/32\lambda/3).

However, the biprism severely refracts the rays (non-paraxial, δ=30∘\delta = 30^\circ), creating two intersecting plane waves.

The true fringe width is a local property of the intersecting waves, given by β=λ/(2sin⁡δ)\beta = \lambda / (2 \sin\delta), which is independent of the screen distance DD.

Using the geometric DD and dd fails because the effective virtual sources are shifted differentially by the large aberration (non-small angle refraction), making the small-angle approximation sin⁡θ≈tan⁡θ\sin\theta \approx \tan\theta invalid.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterRay Optics and Optical Instruments - Class 12
ConceptRay Tracing for Systems
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree