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Question #43211

Difficulty: 8/10 | 🟢 Free

The Question

A stationary point object is placed on the principal axis of a convex lens of focal length f=20 cmf = 20 \text{ cm}. The lens moves towards the object with an unknown, time-varying velocity. A detector tracks the real image formed by the lens. The detector is mounted on a conducting rod of length l=0.5 ml = 0.5 \text{ m} that slides without friction on two parallel conducting rails. The rails are rigidly attached to the lens, parallel to its principal axis, and an ideal inductor of inductance L=10 mHL = 10 \text{ mH} is connected at the lens-end of the rails, forming a closed circuit of negligible resistance. A uniform magnetic field B=2.0 TB = 2.0 \text{ T} exists perpendicular to the plane of the rails. At t=0t=0, the distance between the object and the first principal focus of the lens is x1=50 cmx_1 = 50 \text{ cm}, and the current in the inductor is zero. Find the total magnetic energy stored in the inductor at the instant the distance between the object and the first principal focus becomes x2=10 cmx_2 = 10 \text{ cm}.

Options

  • A.

    5.12 J5.12 \text{ J}

  • B.

    8.00 J8.00 \text{ J}

  • C.

    0.32 J0.32 \text{ J}

  • D.

    10.24 J10.24 \text{ J}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Newton’s Form of Lens Equation|Energy Stored in Inductor|Variable Force Integration

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to couple geometric optics kinematics with electromagnetic induction while navigating a deliberate missing-information trap.

Students often incorrectly assume that calculating the power P=EiP = \mathcal{E}i and integrating it to find energy requires the explicit time-varying velocity function v(t)v(t) of the lens.

By applying Faraday's Law to a purely inductive circuit (E=L di/dt\mathcal{E} = L \, di/dt), the time differential dtdt cancels out, revealing that the change in current depends strictly on the total change in magnetic flux (ΔΦ=LΔi\Delta \Phi = L \Delta i), which is purely a function of spatial displacement.

Furthermore, using Newton's lens equation (xy=f2xy = f^2) elegantly bypasses the sign-convention pitfalls and complex relative velocity derivatives associated with the standard Cartesian lens formula.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterRay Optics and Optical Instruments - Class 12
ConceptNewton’s Form of Lens Equation
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree