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Question #43193
The Question
A monochromatic light beam propagating in vacuum has a wave vector (units: ) and is incident on the flat surface of a uniaxial birefringent crystal. The unit normal vector to the surface, pointing into the crystal, is . The quantity acts as a conserved optical impact parameter across the interface. Inside the crystal, the light splits into an ordinary wave and an extraordinary wave. For the extraordinary wave, let be its wave vector and be its Poynting vector (units: ). The crystal's optic axis is oriented such that it is neither parallel nor perpendicular to the plane of incidence. Which of the following vector relationships is strictly valid for the extraordinary wave at the interface?
Options
- A.
- B.
- C.
- D.
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Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Snell’s Law Vector Form|Impact Parameter Geometry|Tensor Transformation
Why This Question Is Tricky
Common Mistakes
Students incorrectly assume that the direction of energy flow (the ray vector or Poynting vector ) obeys the same coplanarity rules as the wave vector in Snell's law.
In isotropic media, and are parallel, making the refracted ray coplanar with the incident ray and normal.
However, in an anisotropic crystal, boundary conditions only enforce the continuity of the tangential phase (wave vector ).
The extraordinary ray vector decouples from and generally deviates out of the plane of incidence when the optic axis is asymmetric.
This question tests the fundamental distinction between phase velocity direction and group velocity (energy) direction, trapping students who apply scalar Snell's law concepts to the physical ray path in birefringent media.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Ray Optics and Optical Instruments - Class 12 |
| Concept | Snell’s Law Vector Form |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |