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Question #43186

Difficulty: 8/10 | 🟢 Free

The Question

A small cart of mass mm is constrained to move along the positive x-axis (x>0x > 0) on a frictionless horizontal track. It is attached to the origin by a light spring of force constant k=6.4 N/mk = 6.4 \text{ N/m} (natural length is zero). Mounted on the cart is a small concave mirror of focal length f=40 cmf = 40 \text{ cm}. The mirror is mounted on a frictionless pivot, allowing it to rotate freely in the xy-plane. A magnetic dipole of moment μ=2.0 A m2\mu = 2.0 \text{ A m}^2 is rigidly attached to the mirror. The dipole vector μ⃗\vec{\mu} points along the principal axis of the mirror, and the reflecting surface of the mirror faces the direction −μ⃗-\vec{\mu}. The system is placed in a non-uniform magnetic field B⃗=(αx)i^+B1j^\vec{B} = (\alpha x)\hat{i} + B_1\hat{j}, where α=4.0 T/m\alpha = 4.0 \text{ T/m} and B1=3.0 TB_1 = 3.0 \text{ T}. A point object OO is permanently fixed at coordinates (−0.6 m,0.8 m)(-0.6 \text{ m}, 0.8 \text{ m}) in the xy-plane. When the cart and mirror reach their stable equilibrium position and orientation, what are the coordinates of the image of OO formed by the mirror? (Assume the mirror is small enough that the magnetic field is uniform over its volume).

Options

  • A.

    (1.32 m,−1.76 m)(1.32 \text{ m}, -1.76 \text{ m})

  • B.

    (0.60 m,−0.80 m)(0.60 \text{ m}, -0.80 \text{ m})

  • C.

    (0.32 m,−1.76 m)(0.32 \text{ m}, -1.76 \text{ m})

  • D.

    (2.60 m,−0.80 m)(2.60 \text{ m}, -0.80 \text{ m})

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Sign Convention Dynamics|Magnetic Dipole Moment Orientation|Vector Cross-Product

Why This Question Is Tricky

Common Mistakes

This question tests the coupling of magnetic dipole dynamics in a non-uniform field with coordinate-dependent optics.

The primary trap is ignoring the translational force F=∇(μ⃗⋅B⃗)F = \nabla(\vec{\mu} \cdot \vec{B}) exerted by the magnetic field gradient.

Students often mistakenly assume the magnetic field only provides a torque τ⃗=μ⃗×B⃗\vec{\tau} = \vec{\mu} \times \vec{B} to orient the mirror, leading them to incorrectly place the mirror at the origin (the spring's relaxed position).

Furthermore, it rigorously tests the ability to establish a local, rotated Cartesian coordinate system for reflection, requiring vector projections to separate longitudinal and transverse object distances, and correctly mapping the image back to the global frame.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterRay Optics and Optical Instruments - Class 12
ConceptSign Convention Dynamics
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree