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Question #43178
The Question
A perfectly absorbing spherical dust particle of mass and radius is in an unperturbed elliptical orbit around a star of mass . The orbit has a semi-major axis and eccentricity . A uniform, parallel photon beam of constant intensity from a distant quasar illuminates the system. The beam propagates in the plane of the orbit and is perpendicular to the major axis of the ellipse. Assuming the radiation force on the particle is a very small perturbation compared to the gravitational force from the star, and that the star does not shadow the particle, find the magnitude of the change in the particle's orbital angular momentum over one complete revolution.
(Given: is the speed of light in vacuum, is the universal gravitational constant)
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Multi-Concept_Bridge
Master problems that require linking physics and math concepts to solve complex competitive questions.
Concepts Behind This Question
Radiation Pressure|Kepler’s Second Law (Areal Velocity)|Integration
Why This Question Is Tricky
Common Mistakes
This question tests the rigorous application of Keplerian orbital mechanics coupled with non-conservative torques.
A common trap (leading to Option A) is calculating the torque about the geometric center of the ellipse () rather than the focus where the star resides, which yields an incorrect coefficient of 1.
Another trap (leading to Option B) is assuming a uniform rate of change for the eccentric anomaly (), ignoring the factor dictated by Kepler's Second Law, which yields a coefficient of 2.
Students must correctly identify the reference frame (focus) and properly integrate over time using the eccentric anomaly to capture the asymmetric time spent near the apocenter versus the pericenter.
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Electromagnetic Waves - Class 12 |
| Concept | Radiation Pressure |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |