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Question #43163

Difficulty: 8/10 | 🟢 Free

The Question

A region of space (x>0x > 0) is filled with a non-uniform, time-varying dielectric medium. The permittivity of the medium is given by ϵ(x,t)=ϵ0(1+βx)(1+αt)\epsilon(x,t) = \epsilon_0 (1 + \beta x)(1 + \alpha t), where ϵ0\epsilon_0 is the vacuum permittivity, and α\alpha and β\beta are positive constants with units of s−1\text{s}^{-1} and m−1\text{m}^{-1} respectively. The electric field in this region is maintained as E(x,t)=E0ti^\mathbf{E}(x,t) = E_0 t \hat{i}, where E0E_0 is a positive constant with units of V⋅m−1⋅s−1\text{V} \cdot \text{m}^{-1} \cdot \text{s}^{-1} and t>0t > 0 is time. According to the macroscopic Maxwell's equations, which of the following represents the correct expressions for the free volume charge density ρf(x,t)\rho_f(x,t) and the magnitude of the displacement current density Jd(x,t)J_d(x,t) in this medium?

Options

  • A.

    ρf(x,t)=ϵ0E0βt(1+αt)\rho_f(x,t) = \epsilon_0 E_0 \beta t (1 + \alpha t), \quad Jd(x,t)=ϵ0E0(1+βx)(1+2αt)J_d(x,t) = \epsilon_0 E_0 (1 + \beta x)(1 + 2\alpha t)

  • B.

    ρf(x,t)=0\rho_f(x,t) = 0, \quad Jd(x,t)=ϵ0E0(1+βx)(1+αt)J_d(x,t) = \epsilon_0 E_0 (1 + \beta x)(1 + \alpha t)

  • C.

    ρf(x,t)=ϵ0E0βt(1+αt)\rho_f(x,t) = \epsilon_0 E_0 \beta t (1 + \alpha t), \quad Jd(x,t)=ϵ0E0(1+βx)(1+αt)J_d(x,t) = \epsilon_0 E_0 (1 + \beta x)(1 + \alpha t)

  • D.

    ρf(x,t)=ϵ0E0β(1+αt)\rho_f(x,t) = \epsilon_0 E_0 \beta (1 + \alpha t), \quad Jd(x,t)=ϵ0E0(1+2αt)J_d(x,t) = \epsilon_0 E_0 (1 + 2\alpha t)

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Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Maxwell's Correction to Ampere's Law|Gauss Law Applicability|Continuous Charge Distribution

Why This Question Is Tricky

Common Mistakes

This question tests the fundamental definitions of the electric displacement field D\mathbf{D} and its role in the macroscopic Maxwell's equations.

A common trap is conflating the vacuum displacement current ϵ0∂E∂t\epsilon_0 \frac{\partial \mathbf{E}}{\partial t} with the total displacement current ∂D∂t\frac{\partial \mathbf{D}}{\partial t} in a medium.

When the permittivity itself is time-varying, students often incorrectly apply the product rule, either calculating Jd=ϵ∂E∂tJ_d = \epsilon \frac{\partial \mathbf{E}}{\partial t} (ignoring the polarization current arising from changing material properties) or assuming ρf=ϵ0∇⋅E=0\rho_f = \epsilon_0 \nabla \cdot \mathbf{E} = 0 because the electric field is uniform in space.

By requiring the calculation of both ρf\rho_f via ∇⋅D\nabla \cdot \mathbf{D} and JdJ_d via ∂D∂t\frac{\partial \mathbf{D}}{\partial t}, the problem forces a rigorous application of vector calculus to time-varying, non-uniform dielectrics.

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Question Information

SubjectPhysics
ChapterElectromagnetic Waves - Class 12
ConceptMaxwell's Correction to Ampere's Law
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree