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Question #43155

Difficulty: 8/10 | 🟢 Free

The Question

A series LCR circuit consists of an inductor of inductance LL, a capacitor of capacitance CC, a metallic resistor of temperature-independent resistance RmR_m, and a semiconductor resistor of resistance Rs(T)R_s(T). The semiconductor is intrinsic with a band gap energy EgE_g, and its resistance varies with absolute temperature TT strictly due to the intrinsic carrier concentration ni∝exp⁡(−Eg2kBT)n_i \propto \exp\left(-\frac{E_g}{2k_B T}\right), where kBk_B is the Boltzmann constant. At a specific temperature T0T_0, the metallic resistance and the semiconductor resistance are equal, such that Rm=Rs(T0)=R0R_m = R_s(T_0) = R_0. If Q0Q_0 is the quality factor of the circuit at temperature T0T_0, what is the rate of change of the quality factor with respect to temperature, dQdT∣T=T0\left. \frac{dQ}{dT} \right|_{T=T_0}?

Options

  • A.

    Q0Eg4kBT02Q_0 \frac{E_g}{4 k_B T_0^2}

  • B.

    Q0Eg2kBT02Q_0 \frac{E_g}{2 k_B T_0^2}

  • C.

    −Q0Eg4kBT02-Q_0 \frac{E_g}{4 k_B T_0^2}

  • D.

    −Q0Eg2kBT02-Q_0 \frac{E_g}{2 k_B T_0^2}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Frequency Sensitivity of Z|Energy Band Gap Temperature Dependency

Why This Question Is Tricky

Common Mistakes

This question tests the intersection of solid-state physics and AC circuit theory.

The primary trap lies in misapplying the temperature dependence of resistance.

Students often incorrectly assume dRdT>0\frac{dR}{dT} > 0 (as in metals) or forget the negative sign from differentiating 1/T1/T, leading to a negative dQdT\frac{dQ}{dT}.

A secondary trap is ignoring the constant metallic resistance RmR_m in the derivative chain rule, which incorrectly yields a factor of 1/21/2 instead of 1/41/4.

The correct approach requires recognizing that the semiconductor's resistance decreases with temperature, sharpening the resonance peak (increasing Q), and properly accounting for the partial contribution of RsR_s to the total damping resistance.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterAlternating Current - Class 12
ConceptFrequency Sensitivity of Z
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree