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Question #43153

Difficulty: 8/10 | 🟢 Free

The Question

An electron of mass mm and charge −e-e is initially moving in a circular orbit of radius rr with angular velocity ω0\omega_0 in the xyxy-plane. At t=0t=0, a uniform, time-varying magnetic field B⃗(t)=B0sin⁡(Ωt)k^\vec{B}(t) = B_0 \sin(\Omega t) \hat{k} is applied perpendicular to the orbital plane. The field increases from zero to B0B_0 over the time interval 0≤t≤π2Ω0 \le t \le \frac{\pi}{2\Omega}. Assuming the orbital radius rr remains constant due to a strong central restoring force, what is the average power delivered to the electron by the induced electric field during this time interval?

Options

  • A.

    Ωer2B0πω0\frac{\Omega e r^2 B_0}{\pi} \omega_0

  • B.

    Ωer2B0π(ω0+eB04m)\frac{\Omega e r^2 B_0}{\pi} \left( \omega_0 + \frac{e B_0}{4m} \right)

  • C.

    Ωer2B0π(ω0+eB02m)\frac{\Omega e r^2 B_0}{\pi} \left( \omega_0 + \frac{e B_0}{2m} \right)

  • D.

    Ωer2B02π(ω0+eB02m)\frac{\Omega e r^2 B_0}{2\pi} \left( \omega_0 + \frac{e B_0}{2m} \right)

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Multi-Concept_Bridge

Master problems that require linking physics and math concepts to solve complex competitive questions.

Concepts Behind This Question

Average Power over Cycle|Magnetic Moment of Orbiting Electron|Vector Cross-Products

Why This Question Is Tricky

Common Mistakes

This question tests the student's ability to distinguish between the quasi-static potential energy of a magnetic dipole and the dynamic work done by an induced electric field (Faraday's Law).

A common trap is treating the electron's magnetic moment as a static vector μ⃗\vec{\mu} and calculating the work done simply as ΔU=−μ⃗⋅B⃗\Delta U = -\vec{\mu} \cdot \vec{B}, which yields only the first term (leading to Option A).

However, the changing magnetic field induces an EMF that alters the electron's orbital angular momentum (Larmor precession).

Students must apply the Work-Energy Theorem to account for the quadratic dependence of kinetic energy on the changing angular velocity, revealing the additional Larmor precession energy term.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterAlternating Current - Class 12
ConceptAverage Power over Cycle
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree