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Question #43152
The Question
An intrinsic semiconductor component has a temperature-dependent resistance given by , where is the energy band gap, is the Boltzmann constant, and is the absolute temperature. The component is connected to an AC voltage source . The frequency is sufficiently high such that the temperature of the component remains effectively constant at a steady-state value. The component dissipates heat to the surroundings at a constant temperature according to Newton's law of cooling, with a heat transfer coefficient (in ). As the peak voltage is gradually increased, the steady-state temperature increases. However, beyond a critical voltage , thermal runaway occurs and no steady state is possible. Assuming , which of the following expressions best approximates the critical peak voltage ? (Here is the base of the natural logarithm).
Options
- A.
- B.
- C.
- D.
Check Your Answer
Correct Answer
Step-by-Step Solution
Explanation
How the Examiner Thinks
Intuition_Breaker
Train your brain to resist "obvious" answers that are designed to deceive your intuition.
Concepts Behind This Question
Average Power over Cycle|Energy Band Gap Temperature Dependency|Approximation: Taylor Series
Why This Question Is Tricky
Common Mistakes
This question tests the misconception that a system with a negative temperature coefficient of resistance will always reach a stable thermal equilibrium.
Students often incorrectly assume linear resistance or fail to recognize that thermal runaway is a bifurcation point where the derivative of heat generation with respect to temperature equals the heat dissipation coefficient ().
Furthermore, a common trap is forgetting to use the RMS voltage for average power in an AC circuit, leading to a missing factor of 2, or failing to linearize the exponential function correctly around the ambient temperature .
Quick Facts About This Question
Question Information
| Subject | Physics |
| Chapter | Alternating Current - Class 12 |
| Concept | Average Power over Cycle |
| Difficulty | 8 |
| Cognitive Load | 7 |
| Target Solve Time | 160 sec |
| Access | Free |