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Question #43128

Difficulty: 8/10 | 🟢 Free

The Question

A thin equiconvex lens is made of a material with refractive index n0=1.5n_0 = 1.5 at a uniform temperature TrefT_{\text{ref}}. At TrefT_{\text{ref}}, the lens has a central thickness t0=0.5 cmt_0 = 0.5 \text{ cm}, an aperture radius a=1.0 cma = 1.0 \text{ cm}, and a paraxial focal length f0=20.0 cmf_0 = 20.0 \text{ cm} in vacuum. The lens is subjected to a steady radial temperature profile ΔT(r)=T0(ra)2\Delta T(r) = T_0 \left(\frac{r}{a}\right)^2, where rr is the radial distance from the optical axis and T0=100 KT_0 = 100 \text{ K}. The material has a linear thermal expansion coefficient α=8.0×10−5 K−1\alpha = 8.0 \times 10^{-5} \text{ K}^{-1} and a thermo-optic coefficient dndT=β=6.0×10−5 K−1\frac{dn}{dT} = \beta = 6.0 \times 10^{-5} \text{ K}^{-1}. Assume the lens expands locally such that its thickness at distance rr becomes t′(r)=t(r)[1+αΔT(r)]t'(r) = t(r)[1 + \alpha \Delta T(r)], and ignore any radial displacement of the material. Calculate the new effective paraxial focal length ff of the lens.

Options

  • A.

    25.0 cm25.0 \text{ cm}

  • B.

    20.0 cm20.0 \text{ cm}

  • C.

    16.7 cm16.7 \text{ cm}

  • D.

    22.7 cm22.7 \text{ cm}

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Correct Answer

Step-by-Step Solution

Explanation

How the Examiner Thinks

Variable_Constraint

Develop pure symbolic logic skills by mastering algebraic constraints without relying on numerical data.

Concepts Behind This Question

Lens Maker’s Formula Constraints|Thermal Expansion of Area and Volume|Integration

Why This Question Is Tricky

Common Mistakes

Students often incorrectly assume that paraxial properties are strictly determined by the conditions exactly at the optical axis (r=0r=0).

Since ΔT(0)=0\Delta T(0) = 0, they fall into the trap of concluding the focal length remains unchanged (20.0 cm20.0 \text{ cm}).

This misapplication ignores that paraxial focusing depends on the wavefront's curvature (the second spatial derivative of the Optical Path Length).

A radial temperature gradient causes differential thermal expansion that flattens the physical curvature at the center, and simultaneously creates a Gradient-Index (GRIN) profile.

Both effects contribute an r2r^2-dependent phase shift that fundamentally alters the optical power, requiring an integration of the local deformations and index changes across the aperture.

Quick Facts About This Question

Question Information

SubjectPhysics
ChapterRay Optics and Optical Instruments - Class 12
ConceptLens Maker’s Formula Constraints
Difficulty8
Cognitive Load7
Target Solve Time160 sec
AccessFree